如何在列表中的某个点之后从字符串中删除字符？

Question

我在列表中有一个字符串列表，我想删除第十个字符之后的每个字符串中的所有内容。

EX：

['0.04112243,0.04112243,right,4.11%', '0.12733313,0.05733313,right,12.73%', '0.09203131,0.02203131,right,9.2%']

我只想要列表中的前十个整数，其他所有内容都应该从中删除。

输出

['0.04112243', '0.12733313', '0.09203131']

Answer 1

您可以使用列表理解：

original = ['0.04112243,0.04112243,right,4.11%', '0.12733313,0.05733313,right,12.73%', '0.09203131,0.02203131,right,9.2%']

new = [s[:10] for s in original]

输出：

['0.04112243', '0.12733313', '0.09203131']

如果您想将所有内容保留在第一个逗号之前，也可以更加灵活一些：

new = [s.partition(',')[0] for s in original]

Answer 2

您可以访问类似于数组的字符串字符。

代码：

example = ['0.04112243,0.04112243,right,4.11%', '0.12733313,0.05733313,right,12.73%', '0.09203131,0.02203131,right,9.2%']
for s in example:
    print(s[:10])

输出：

0.04112243
0.12733313
0.09203131

Answer 3

列表理解和字符串切片：

dirty = ['0.04112243,0.04112243,right,4.11%', '0.12733313,0.05733313,right,12.73%', '0.09203131,0.02203131,right,9.2%']

clean = [num[:10] for num in dirty]

Answer 4

Split（）创建一个由指定字符分隔的字符串列表。考虑到这一点，我将在逗号（，）char上拆分每个字符串，然后将第一个元素附加到列表中。

lst = ['0.04112243,0.04112243,right,4.11%', '0.12733313,0.05733313,right,12.73%', '0.09203131,0.02203131,right,9.2%']
result = []
for i in lst:
    result.append(i.split(",")[0])
#Test output
print(result)

这应该以所需的格式返回所需的值！ 希望这会有所帮助。