Question

我有一组地址存储为单独的字符串。这是这些字符串的可能值：

"Staples Center, 555 Test Drive, Los Angeles, CA 98112"
"555 Test Drive, Los Angeles, CA 98112"
"Los Angeles, CA"
"Los Angeles, CA 98112"
"Los Angeles"

日期将始终采用这种格式，其中可以包含场所名称，街道地址，城市，州和邮政编码

我只想从这些字符串中动态提取城市和州：

$addresses_array = array(
    "Staples Center, 555 Test Drive, Los Angeles, CA 98112",
    "555 Test Drive, Los Angeles, CA 98112",
    "Los Angeles, CA",
    "Los Angeles, CA 98112",
    "Los Angeles"
);

foreach ($addresses_array as $address) {
    if (strpos($address, ',') !== false) {
        // extract the city and state
    }
}

鉴于地址值的模式，我是否可以做一些事情来基于逗号提取城市和州？

我看到的是城市将永远是字符串中的最后一个逗号。

Answer 1

如果我没看错的话，您需要最后两个项目（如果有）。
使用爆炸，然后内爆最后两个项目。

$addresses_array = array(
    "Staples Center, 555 Test Drive, Los Angeles, CA 98112",
    "555 Test Drive, Los Angeles, CA 98112",
    "Los Angeles, CA",
    "Los Angeles, CA 98112",
    "Los Angeles"
);

foreach ($addresses_array as &$address) {
    $arr = explode(", ", $address);
    $address = implode(", ", array_slice($arr, -2));
}

var_dump($addresses_array);

输出：

array(5) {
  [0]=>
  string(21) "Los Angeles, CA 98112"
  [1]=>
  string(21) "Los Angeles, CA 98112"
  [2]=>
  string(15) "Los Angeles, CA"
  [3]=>
  string(21) "Los Angeles, CA 98112"
  [4]=>
  &string(11) "Los Angeles"
}

https://3v4l.org/Gqcid

如果您不希望使用zip，那么如果$ arr计数大于一个，则可以爆炸空间中的最后一个项目。

foreach ($addresses_array as &$address) {
    $arr = explode(", ", $address);
    if(count($arr) >1){
        $arr[count($arr)-1] = explode(" ", $arr[count($arr)-1])[0];
        $address = implode(", ", array_slice($arr, -2));
    }
}

输出：

array(5) {
  [0]=>
  string(15) "Los Angeles, CA"
  [1]=>
  string(15) "Los Angeles, CA"
  [2]=>
  string(15) "Los Angeles, CA"
  [3]=>
  string(15) "Los Angeles, CA"
  [4]=>
  &string(11) "Los Angeles"
}

https://3v4l.org/uKvke

Answer 2

您可以同时使用explode和count功能


$addresses_array = array(
    "Staples Center, 555 Test Drive, Los Angeles, CA 98112",
    "555 Test Drive, Los Angeles, CA 98112",
    "Los Angeles, CA",
    "Los Angeles, CA 98112",
    "Los Angeles"
);


foreach ($addresses_array as $address) {
    $addr = explode(",",$address);
    switch (count($addr))
    {
        case 1:
        case 2:
            echo  $addr[0];
            break;
        case 3:
            echo  $addr[1];
            break;
        case 4:
            echo  $addr[2];
            break;

    }
}

按照特定格式从完整的地址字符串中提取城市和州

2 个答案: