我正在尝试解析此网址 http://rssmix.com/u/8304287/rss.xml
我已经尝试过从网站上获得的这段代码,使用自己的链接可以正常工作,但是当我在链接上进行尝试时,它只会显示前3个元素的结果。我想解析整个XML,但我不知道错误可能在for循环中,或者有什么需要帮助的地方。谢谢。
public class MainActivity extends AppCompatActivity {
// Declare variables
TextView textview;
NodeList nodelist;
ProgressDialog pDialog;
// Insert image URL
String URL = "http://rssmix.com/u/8304287/rss.xml";
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
// Locate a TextView in your activity_main.xml layout
textview = (TextView) findViewById(R.id.text);
// Execute DownloadXML AsyncTask
new DownloadXML().execute(URL);
}
// DownloadXML AsyncTask
private class DownloadXML extends AsyncTask<String, Void, Void> {
@Override
protected void onPreExecute() {
super.onPreExecute();
// Create a progressbar
pDialog = new ProgressDialog(MainActivity.this);
// Set progressbar title
pDialog.setTitle("Android Simple XML Parsing using DOM Tutorial");
// Set progressbar message
pDialog.setMessage("Loading...");
pDialog.setIndeterminate(false);
// Show progressbar
pDialog.show();
}
@Override
protected Void doInBackground(String... Url) {
try {
URL url = new URL(Url[0]);
DocumentBuilderFactory dbf = DocumentBuilderFactory
.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
// Download the XML file
Document doc = db.parse(new InputSource(url.openStream()));
// doc.getDocumentElement();
// Locate the Tag Name
nodelist = doc.getElementsByTagName("channel");
Log.v("BIGASS",doc.toString());
} catch (Exception e) {
Log.e("Error", e.getMessage());
e.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(Void args) {
for (int temp = 0; temp < nodelist.getLength(); temp++) {
Node nNode = nodelist.item(temp);
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
// Set the texts into TextViews from item nodes
// Get the title
textview.setText(textview.getText() + "Title : "
+ getNode("title", eElement) + "\n" + "\n");
// Get the description
textview.setText(textview.getText() + "Description : "
+ getNode("description", eElement) + "\n" + "\n");
// Get the link
textview.setText(textview.getText() + "Link : "
+ getNode("link", eElement) + "\n" + "\n");
// Get the date
}
}
// Close progressbar
pDialog.dismiss();
}
}
// getNode function
private static String getNode(String sTag, Element eElement) {
NodeList nlList = eElement.getElementsByTagName(sTag).item(0)
.getChildNodes();
Node nValue = (Node) nlList.item(0);
return nValue.getNodeValue();
}
}
答案 0 :(得分:0)
在您的xml中,执行时结果只有一个频道标签
nodelist = doc.getElementsByTagName("channel");
您将仅获得一个元素。 我的理解是,您需要所有项目的列表,为此您应该执行
items = channelNode.getElementsByTagName("item");
在您的for循环中。
您的doPost方法看起来像这样
@Override
protected void onPostExecute(Void args) {
for (int temp = 0; temp < nodelist.getLength(); temp++) {
Node nNode = nodelist.item(temp);// This will be your channel node
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
//here call
List<Elements> items=eElement.getElementsByTagName("item") //This is give list of all items
//loop over the items and parse title,description and link.
}
}