Question

我想创建Alamofire POST请求但是我收到失败响应，我不知道映射对象或请求中的错误

   func loginUser() {
        let URL = ..... + "/Login"
        let params2 = "{\"MobileNumber\":\"\(MobileNumber.text!)\"}"
        Alamofire.request(URL, method: .post, parameters: [:], encoding: params2, headers: [
            "Content-Type": "application/json"]).responseObject { (response: DataResponse<Login>) in
                if(response.result.isFailure){
                  print ("failure")
                    print (response.result.description)
                    return
                }
                else{
                    print(response.result)   // result of response serialization
                    self.LoginUser = response.result.value
                }

        }

Answer 1

似乎您正在将请求方法的编码属性设置为param2变量。

尝试将参数设置为param2并更新编码以使用.default：

Alamofire.request(URL, method: .post, parameters: param2, encoding: .default, headers: ...

Answer 2

您没有将正确的值传递到必填字段中。请在下面使用更正的版本，希望对您有帮助

    func loginUser() {
            let URL = ..... + "/Login"
            let params2: [String: Any] = ["MobileNumber" : "\(MobileNumber.text!)"]"
let header = ["Content-Type": "application/json"]
            Alamofire.request(URL, method: .post, parameters: params2, encoding: JSONEncoding.default, headers: header).responseObject { (response: DataResponse<Login>) in
                    if(response.result.isFailure){
                      print ("failure")
                        print (response.result.description)
                        return
                    }
                    else{
                        print(response.result)   // result of response serialization
                        self.LoginUser = response.result.value
                    }

            }

发布方法请求Alamofire（responseObject）

2 个答案: