Question

需要两个相似表的合计结果而不会重复。

表具有相似的结构。（日期，帐单编号，载体编号，持续时间...）表格是2019-01-29和2019-01-30

我尝试了相同查询的UNION，但是得到了重复的条目。

 select billed_number, sum(CASE WHEN [account_billed_duration] > 0 THEN 1 END) AS completed
 from alex4..[2019-01-29]
 where billed_number = '702640'
 and carrier_id = 171
 group by billed_number

 union all

 select billed_number, sum(CASE WHEN [account_billed_duration] > 0 THEN 1 END) AS completed
 from alex4..[2019-01-30]
 where billed_number = '702640'
 and carrier_id = 171
 group by billed_number

在此示例中，我仅使用表格（[2019-01-29]和[2019-01-30]）我还需要能够合并两个以上的表。

结果： billed_number，已完成 702640 3735 702640 3539

预期结果： billed_number，已完成 702640 7274

Answer 1

使用联合工会不确实的所有与重复结合所有结果

Answer 2

感谢您的答复。实际上，我同时尝试了UNION和UNION ALL，并获得了相同的结果。

我昨晚起床，直到我弄清楚了。子查询可以解决问题...

 SELECT  distinct  billed_number , sum(completed)as comp , FROM    (
        SELECT  [billed_number], 
        sum(CASE WHEN [account_billed_duration] > 0 THEN 1 END) AS completed,
        sum(CASE WHEN [account_billed_duration] = 0 THEN 1 END) AS failed
        FROM alex4..[2019-01-29]
 where billed_number = '702640'
 and carrier_id = 171
 group by billed_number --,account_billed_duration
        UNION
        SELECT  [billed_number], 
        sum(CASE WHEN [account_billed_duration] > 0 THEN 1 END) AS completed,
        sum(CASE WHEN [account_billed_duration] = 0 THEN 1 END) AS failed
        FROM    alex4..[2019-01-30]
 where billed_number = '702640'
 and carrier_id = 171
 group by billed_number --, account_billed_duration
    ) Q
    group by billed_number

再次感谢您的回复：-）

创建查询以将两个表中的数据与相似数据合并

2 个答案: