Question

此代码可以正常工作，但不会在模板中显示“ {{skill.skillName}}” 那是什么问题呢？

这是结果时，我尝试打印skills从视图

<QuerySet [<Skill: nope>, <Skill: yep>, <Skill: yes>]>

models.py

class User_Model(models.Model):
    firstname = models.CharField(max_length=100)
    lastname = models.CharField(max_length=100)
    user = models.OneToOneField(User, on_delete=models.CASCADE)
    country = models.CharField(max_length=50)
    city = models.CharField(max_length=50)
    job = models.CharField(max_length=100)
    phoneNumber = models.PositiveIntegerField()
    description = models.CharField(max_length=600)
    profilePicture = models.ImageField(upload_to='users/', default='users/user-man1.jpg')
    def __str__(self):
        return self.user.username

class Skill(models.Model):
    skillName = models.CharField(max_length=30, null=True)
    user = models.ManyToManyField(User)

    def __str__(self):
        return self.skillName

views.py

def memberOnlyDetail(request, username):
    user = User.objects.get(username=username)
    skills = Skill.objects.filter(user=user)
    memberDetails =User_Model.objects.get(user=user)

    return render(request, 'memberMemberProfilePage.html', {'memberDetails': memberDetails}, {'skills': skills})
    enter code here

memberMemberProfilePage.html

{%for skill in skills%}
<div class="col-lg-2 col-md-3 col-sm-6 hvr-grow-rotate">
    <p>{{skill1.skillName}}</p>
</div>
{%endfor%}

Answer 1

这里的问题是使用render()功能。

下面是从签名的django documentation：
render(request, template_name, context=None, content_type=None, status=None, using=None)

现在让我们来看看参数你逝去的：

render(request, 'memberMemberProfilePage.html', {'memberDetails': memberDetails}, {'skills': skills})

当您正确地将request，template_name和{'memberDetails': memberDetails}传递为context时，您将{'skills': skills}传递为第四个参数，即{{1} }。

要在您的上下文中正确传递content_type，只需将其包括在上下文字典中，如下所示：

skills

在模板中显示数据时出现问题

1 个答案: