Question

我有一个数字列表，我想计算一下附近有多少相同的物品。然后，我想创建一个新列表，该列表将数字中出现的次数相乘。

列表[1, 2, 2, 3, 4, 4, 3]
输出将为[1, 2, 2, 2, 2, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 3, 3, 3]

def multiply_lst(lst):    
    new_lst = []    
    counter = 1    
    for i in range(len(lst)-1):  
        if lst[i] == lst[i+1]  
            counter+=1  
        else:  
            new_lst += lst[i]*(1*lst[i])  
        new_lst += [lst[i]]*(counter*lst[i])  
return new_lst

Answer 1

这可能很复杂，但您也可以通过遵循以下解决方案来实现自己的目标：

def multiply_lst(given_list):
    counter_list = []   # list to collect counter for each of the different numbers
    different_numbers_list = [given_list[0]]  # list collect each of the different numbers and add the first different number from given_list
    result_list = []  # list for the result
    count = 1   # set count to 1

    # loop through the given list
    for i in range(1, len(given_list)):
        # if current number and next number are same add 1 to count
        if given_list[i] == given_list[i-1]:
            count += 1
        # else the number to different_numbers_list and add the counter for the number to counter_list and then set count to 1
        else:
            different_numbers_list.append(given_list[i])
            counter_list.append(count)
            count = 1

    counter_list.append(count)  # add the last different number's count to the counter_list

    # finally add items from different_numbers_list, (item * items_counter from counter_list) times to result_list
    for i in range(len(different_numbers_list)):
        for j in range(counter_list[i]*different_numbers_list[i]):
            result_list.append(different_numbers_list[i])

    return result_list

lst = [1, 2, 2, 3, 4, 4, 3]    # given list
print(multiply_lst(lst))

Answer 2

您可以在列表中添加一个新列表，其中包含重复<selector <item android:state_pressed="false" android:drawable="@drawable/ic_normal_button" <item android:state_pressed="true" android:drawable="@drawable/ic_pressed_button"/> </selector>次的数字x。

如何计算列表中有多少附近的相同项目

2 个答案: