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Question

我有一个c＃脚本，可在其中创建当年，当月，当周和当日的时间戳。

DateTime now = DateTime.UtcNow;

now = new DateTime(now.Year, 1, 1);
int yearDay = (int)(now.Subtract(new DateTime(1970, 1, 1))).TotalSeconds;

now = new DateTime(now.Year, now.Month, 1);
int monthDay = (int)(now.Subtract(new DateTime(1970, 1, 1))).TotalSeconds;

now = DateTime.UtcNow.StartOfWeek(DayOfWeek.Monday);
int weekDay = (int)(now.Subtract(new DateTime(1970, 1, 1))).TotalSeconds;

now = new DateTime(now.Year, now.Month, now.Day);
int toDay = (int)(now.Subtract(new DateTime(1970, 1, 1))).TotalSeconds;

现在我想完成同样的工作，但是在javascript中...我已经有了适当的年份，但是不确定如何获取月，周和日。

var d = new Date();

// YEAR TIMESTAMP //
var thisYear = d.getUTCFullYear();
var y = Date.UTC(thisYear, 0, 1, 0, 0, 0, 0);
var yearDay = Math.floor(y / 1000);

希望有人能帮助我在这个问题上和在此先感谢： - ）

我也有这样的月份，但仍然需要弄清楚如何获取当前的日期和周数。

// MONTH TIMESTAMP //
var thisMonth = d.getUTCMonth();
var m = Date.UTC(thisYear, thisMonth, 1, 0, 0, 0, 0);
var monthDay = Math.floor(m / 1000);

// C# toDay output: 1548979200
// C# weekDay output: 1548633600

试过这种今天但输出是不一样的在C＃：

// DAY TIMESTAMP //
var thisDay = d.getUTCDay();
var da = Date.UTC(thisYear, thisMonth, thisDay, 0, 0, 0, 0);
var toDay = Math.floor(da / 1000);

// output: 1549324800

仍然希望获得帮助：-）

*********编辑2 ***********

好的，我终于有了正确的一天：

// DAY TIMESTAMP //
var da = Date.UTC(thisYear, thisMonth, thisDay, 0, 0, 0, 0);
var toDay = Math.floor(da / 1000);

现在剩下的就是如何使星期正确。

我已经尝试过了：

// WEEK TIMESTAMP //
var w = Date.UTC(thisYear, thisMonth, d.setDate(d.getDate() - (d.getDay() || 7) + 1), 0, 0, 0, 0);
var weekDay = Math.floor(w / 1000);

这将输出NaN。关于如何实现此目标的任何想法？

Answer 1

您是否已在MDN上签出Date参考？

存在检索此信息的方法。

// Vanilla JS
var utcDate = new Date();
console.log({
  yearDay: utcDate.getUTCFullYear(),
  monthDay: utcDate.getUTCMonth(),
  weekDay: utcDate.getUTCDay(),
  toDay: utcDate.getUTCDate(),
  hour: utcDate.getUTCHours(),
  min: utcDate.getUTCMinutes(), 
  sec: utcDate.getUTCSeconds(),
  ms: utcDate.getUTCMilliseconds()
});

// Moment
var utcMoment = moment.utc();
console.log({
  yearDay: utcMoment.year(),
  monthDay: utcMoment.month(),
  weekDay: utcMoment.isoWeekday(),
  toDay: utcMoment.date(), // Day of month or utcMoment.dayOfYear(),
  hour: utcMoment.hours(),
  min: utcMoment.minutes(), 
  sec: utcMoment.seconds(),
  ms: utcMoment.milliseconds()
});

.as-console-wrapper { top: 0; max-height: 100% !important; }

<script src="https://momentjs.com/downloads/moment.min.js"></script>

更新

如果要获取一周中特定日期的日期，则可以克隆日期，以天为单位计算差异，然后从当前日期减去/减去这些天数。

const TimeUnit = {
  YEARS : {
    add : function(date, amount, utc) {
      if (utc) date.setUTCFullYear(date.getUTCFullYear() + amount);
      else date.setUTCFullYear(date.getUTCFullYear() + amount);
      return date;
    }
  },
  MONTHS : {
    add : function(date, amount, utc) {
      if (utc) date.setUTCMonth(date.getUTCMonth() + amount);
      else date.setMonth(date.getMonth() + amount);
      return date;
    }
  },
  DAYS : {
    add : function(date, amount, utc) {
      if (utc) date.setUTCDate(date.getUTCDate() + amount);
      else date.setDate(date.getDate() + amount);
      return date;
    }
  },
  HOURS : {
    add : function(date, amount, utc) {
      if (utc) date.setUTCHours(date.getUTCHours() + amount);
      else date.setHours(date.getHours() + amount);
      return date;
    }
  },
  MINUTES : {
    add : function(date, amount, utc) {
      if (utc) date.setUTCMinutes(date.getUTCMinutes() + amount);
      else date.setMinutes(date.getMinutes() + amount);
      return date;
    }
  },
  SECONDS : {
    add : function(date, amount, utc) {
      if (utc) date.setUTCSeconds(date.getUTCSeconds() + amount);
      else date.setSeconds(date.getSeconds() + amount);
      return date;
    }
  },
  MILLISECONDS : {
    add : function(date, amount, utc) {
      if (utc) date.setUTCMilliseconds(date.getUTCMilliseconds() + amount);
      else date.setMilliseconds(date.getMilliseconds() + amount);
      return date;
    }
  }
};

function addTime(date, timeUnit, amount, utc) {
  return timeUnit.add(date, amount, utc);
}

function getDateForCurrentWeek(date, dayOfWeek, utc) {
  var clone = new Date(date.getTime());
  var currentDay = (utc ? clone.getUTCDay() : clone.getDay()) || 7;
  var diff = dayOfWeek - currentDay + 1;
  return addTime(clone, TimeUnit.DAYS, diff, utc);
}

function printDate(targetEl, date, utc) {
  targetEl.value = JSON.stringify(utc ? {
    year: date.getUTCFullYear(),
    month: date.getUTCMonth() + 1,
    dayOfWeek: date.getUTCDay(),
    date: date.getUTCDate(),
    hour: date.getUTCHours(),
    min: date.getUTCMinutes(), 
    sec: date.getUTCSeconds(),
    ms: date.getUTCMilliseconds()
  } : {
    year: date.getFullYear(),
    month: date.getMonth() + 1,
    dayOfWeek: date.getDay(),
    date: date.getDate(),
    hour: date.getHours(),
    min: date.getMinutes(), 
    sec: date.getSeconds(),
    ms: date.getMilliseconds()
  }, null, 2);
}

function setDayOfWeekValue(selector, date, dayOfWeek, utc) {
  document.querySelector(selector).value = getDateForCurrentWeek(date, dayOfWeek, utc);
}

var utcDate = new Date();
setDayOfWeekValue('.day-sun', utcDate, 0, true);
setDayOfWeekValue('.day-mon', utcDate, 1, true);
setDayOfWeekValue('.day-tue', utcDate, 2, true);
setDayOfWeekValue('.day-wed', utcDate, 3, true);
setDayOfWeekValue('.day-thu', utcDate, 4, true);
setDayOfWeekValue('.day-fri', utcDate, 5, true);
setDayOfWeekValue('.day-sat', utcDate, 6, true);

// Test adding 1 unit to each date portion.
printDate(document.getElementById('result-1'), utcDate, true);
utcDate = addTime(utcDate, TimeUnit.YEARS, 1, true);
utcDate = addTime(utcDate, TimeUnit.MONTHS, 1, true);
utcDate = addTime(utcDate, TimeUnit.DAYS, 1, true);
utcDate = addTime(utcDate, TimeUnit.HOURS, 1, true);
utcDate = addTime(utcDate, TimeUnit.MINUTES, 1, true);
utcDate = addTime(utcDate, TimeUnit.SECONDS, 1, true);
utcDate = addTime(utcDate, TimeUnit.MILLISECONDS, 1, true);
printDate(document.getElementById('result-2'), utcDate, true);

.days-of-week .day-of-week {
  margin-bottom: 0.25em;
}
.days-of-week label {
  display: inline-block;
  font-weight: bold;
  width: 3em;
}
.days-of-week input[class^="day-"] {
  font-family: monospace;
  width: 80vw;
}

<div class="days-of-week">
  <div class="day-of-week"><label>Sun</label><input type="text" class="day-sun" /></div>
  <div class="day-of-week"><label>Mon</label><input type="text" class="day-mon" /></div>
  <div class="day-of-week"><label>Tue</label><input type="text" class="day-tue" /></div>
  <div class="day-of-week"><label>Wed</label><input type="text" class="day-wed" /></div>
  <div class="day-of-week"><label>Thu</label><input type="text" class="day-thu" /></div>
  <div class="day-of-week"><label>Fri</label><input type="text" class="day-fri" /></div>
  <div class="day-of-week"><label>Sat</label><input type="text" class="day-sat" /></div>
</div>

<textarea id="result-1" rows="12" cols="32"></textarea>
<textarea id="result-2" rows="12" cols="32"></textarea>

Answer 2

要在一周的开始获得星期一，您可以减去天数再加一个。星期日是0，因此要获取上一个星期一，请将其天数更改为7。

您使用的代码不正确，d.setDate(...)返回所需的调整日期的时间值。你不需要做其他事情。但是，由于您使用的是UTC值，因此这取决于您的情况。

我更改了变量名称，以包括UTC作为其值的提示。同样，“日期”方法返回月份中的天数，“日期”方法返回一周中的天数。

var d = new Date();
var utcYear = d.getUTCFullYear();
// Only year and month need to be set, missing values will default to minimums
var yearDay = Math.floor(Date.UTC(utcYear, 0) / 1000);

// MONTH TIMESTAMP //
var utcMonth = d.getUTCMonth();
var monthDay = Math.floor(Date.UTC(utcYear, utcMonth) / 1000);

// DAY TIMESTAMP // - changed "Day" to "Date"
var utcDate = d.getUTCDate();
var toDay = Math.floor(Date.UTC(utcYear, utcMonth, utcDate) / 1000);

// WEEK TIMESTAMP //
var w = new Date(Date.UTC(utcYear, utcMonth, utcDate));

// Set w to Monday at start of week
w.setUTCDate(w.getUTCDate() - (w.getUTCDay() || 7) + 1);

var weekDay = Math.floor(w / 1000);

console.log(yearDay, monthDay, toDay, weekDay);

将C＃时间戳转换为javascript时间戳

2 个答案:

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