Question

let wordarray=[“defeat”,”dead”,”eaten”,”defend”,”ante”];
word =“defantmsi”;
posarray=“entfdenis”;

我是JavaScript的新手，并且在某个地方停留了一段代码。实际上，我想同时比较'word'和'posarray'并在'posarray'中找到丢失的字符，即'm'和'a'，然后我必须在'wordarray'中找到字符串及其位置， t包含那些字符（m和a）。那么如何仅使用JavaScript来做到这一点呢？

预期的输出将是不包含字符m的a字符串和一个保卫的字符串。

Answer 1

您可以使用filter和every

首先，我们通过与word进行比较，从posarray中获取丢失的字符。比起我们使用wordarray和every来检查includes条件来过滤and

let wordarray=['defeat','dead','eaten','defend','ante', 'xyzam'];
let word ='defantmsi';
let posarray='entfdenis';

let missing = word.split('').filter(e=> !posarray.includes(e))


let op = wordarray.filter(e=> !missing.every(el=>e.includes(el)))


console.log(op)

Answer 2

下面是您的示例代码

let wordarray=["defeat","dead","eaten","defend","ante","something"];
word ="defantmsi";
posarray="entfdenis";
function findMissingCharacters(str1,str2){
	let result = [] //array which will be returned
	for(let letter of str1){
    //check if str2 doesnot contain letter of str1
		if(!str2.includes(letter)) result.push(letter);
	}
	return result;
}
let missing = findMissingCharacters(word,posarray);
//filtering the wordarray
let strings = wordarray.filter(word =>{
  //this boolean will be returned
	let contains = false;
	missing.forEach(letter => {
    //check if any of letter in missing is in word
		if(word.includes(letter)) contains = true;
	})
  //we don't want strings for which contains is true
	return !contains;
})
console.log(strings);

在数组中找到不包含JavaScript中字符的字符串

2 个答案: