我正在尝试为编译时积分序列实现某些功能。下面是该操作的实现或:
events: [
{% for i in events %}
{
resourceId:'{{i.resource_id}}',
title: '{{ i.event_name}}',
start: '{{ i.start_date|date:"Y-m-d" }}',
end: '{{ i.end_date|date:"Y-m-d" }}',
},
{% endfor %}
],
我尝试了几种情况,通过VC ++(19.16.27026.1)检查程序,很多情况下导致编译器错误:
#include <cstdint>
#include <utility>
using UInt32 = std::uint32_t;
template<UInt32... s>
using Sequence = std::integer_sequence<UInt32, s...>;
template<UInt32>
constexpr bool find([[maybe_unused]] Sequence<> a = {}) noexcept {
return false;
}
template<UInt32 x, UInt32 v, UInt32... s>
constexpr bool find([[maybe_unused]] Sequence<v, s...> a = {}) noexcept {
if constexpr (v == x) {
return true;
} else {
return find<x, s...>();
}
}
constexpr auto operator|(Sequence<>, Sequence<>) noexcept {
return Sequence<>{};
}
template<UInt32 v, UInt32... s>
constexpr auto operator|(Sequence<v, s...>, Sequence<>) noexcept {
return Sequence<v, s...>{};
}
template<UInt32... s, UInt32 x, UInt32... t>
constexpr auto operator|(Sequence<s...>, Sequence<x, t...>) noexcept {
if constexpr (find<x, s...>()) {
return Sequence<s...>{} | Sequence<t...>{};
} else {
return Sequence<s..., x>{} | Sequence<t...>{}; // error C2679
}
}
例如:
Error C2679 binary '|': no operator found which takes a right-hand operand of type 'std::integer_sequence<uint32_t,4,5>' (or there is no acceptable conversion)
我尝试了其他编译器,例如GCC 8.2.0和Clang 7.0.0。他们会编译所有没有错误的案例。
我不明白为什么会发生此错误。有什么想法吗?
答案 0 :(得分:0)
我了解为什么会发生错误。
考虑以下示例:
#include <cstdint>
#include <utility>
using UInt32 = std::uint32_t;
template<UInt32... s>
using Sequence = std::integer_sequence<UInt32, s...>;
template<UInt32... s, UInt32 x, UInt32... t>
constexpr auto foo(Sequence<s...>, Sequence<x, t...>) noexcept {
return 0;
}
int main() {
[[maybe_unused]] constexpr auto a = foo(Sequence<1, 2>{}, Sequence<3, 4, 5>{});
[[maybe_unused]] constexpr auto b = foo(Sequence<1, 2, 3>{}, Sequence<4, 5>{});
}
GCC 8.2.0和Clang 7.0.0编译成功编译了它。但VC ++(VS 2017)生成以下错误:
Error C2664: 'int func<1,2,3,4,5>(std::integer_sequence<uint32_t,1,2>,std::integer_sequence<uint32_t,3,4,5>) noexcept': cannot convert argument 1 from 'std::integer_sequence<uint32_t,1,2,3>' to 'std::integer_sequence<uint32_t,1,2>'
从错误中您可以看到,由于函数模板的参数列表和模板化类型的重合,编译器尝试b
对a
使用已经定义的函数,导致失败的原因是,最终的功能参数类型不同。其他两个编译器定义了一个新函数,其中包含b
的新类型:
a: foo<1, 2, 3, 4, 5>(Sequence<1, 2>, Sequence<3, 4, 5>)
b: foo<1, 2, 3, 4, 5>(Sequence<1, 2, 3>, Sequence<4, 5>)
因此,在计算Sequence<1>{} | Sequence<3, 4, 5>{}
时出现以下情况:
constexpr auto operator|<1, 2, 3, 4, 5>(Sequence<1, 2>, Sequence<3, 4, 5>) noexcept {
if constexpr (find<3, 1, 2>()) { // false
return Sequence<1, 2>{} | Sequence<3, 4, 5>{};
} else {
return Sequence<1, 2, 3>{} | Sequence<4, 5>{}; // error C2679
}
}
试图使用编译器operator|<1, 2, 4, 5>(Sequence<1, 2>, Sequence<3, 4, 5>)
。
现在知道了问题的实质,我能够改写的解决方案,以便它可以由所有三个编译器编译:
using UInt32 = std::uint32_t;
template<UInt32... s>
struct Sequence {};
template<template<UInt32...> typename S, UInt32... s>
constexpr bool empty([[maybe_unused]] S<s...> a = {}) noexcept {
return sizeof...(s) == 0;
}
template<template<UInt32...> typename S, UInt32 x, UInt32... s>
constexpr UInt32 first([[maybe_unused]] S<x, s...> a = {}) noexcept {
return x;
}
template<template<UInt32...> typename S>
constexpr auto tail([[maybe_unused]] S<> a = {}) noexcept {
return S<>{};
}
template<template<UInt32...> typename S, UInt32 x, UInt32... s>
constexpr auto tail([[maybe_unused]] S<x, s...> a = {}) noexcept {
return S<s...>{};
}
template<UInt32 x, template<UInt32...> typename S>
constexpr bool find([[maybe_unused]] S<> a = {}) noexcept {
return false;
}
template<UInt32 x, template<UInt32...> typename S, UInt32 v, UInt32... s>
constexpr bool find([[maybe_unused]] S<v, s...> a = {}) noexcept {
if constexpr (v == x) {
return true;
} else {
return find<x>(S<s...>{});
}
}
template<UInt32... s, typename S2>
constexpr auto operator|(Sequence<s...>, S2) noexcept {
if constexpr (sizeof...(s) == 0) {
return S2{};
} else if constexpr (empty(S2{})) {
return Sequence<s...>{};
} else {
constexpr auto x = first(S2{});
if constexpr (find<x>(Sequence<s...>{})) {
return Sequence<s...>{} | tail(S2{});
} else {
return Sequence<s..., x>{} | tail(S2{});
}
}
}