Question

我知道这个问题可能经常被问到，但是我一直在尝试通过左联接找到问题。我四处搜寻并尝试了一些不同的方法，但是仍然无法确定问题所在。

left join (
    SELECT
        MAX(e.date) as MaxDate
        ,e.patientID
    FROM
        labdata ld
        inner join enc e on e.encounterID = ld.EncounterId
            and e.deleteFlag = 0
            and ld.deleteFlag = 0
            and ld.futureflag = 0
            and ld.cancelled = 0
            and ld.received = 1
        inner join @patients t on t.patientID = e.patientID
        inner join structsocialhistory SSH on SSH.encounterId = e.encounterID
        INNER JOIN (structdatadetail SDD ON SSH.catid = SDD.catid      
                AND     SSH.itemid = SDD.itemid 
                AND   SSH.detailid = SDD.id)
        WHERE SSH.catid  = 10619
        AND SSH.itemid = 318681 
        AND SSH.detailID = 49 AND SSH.ValueID =82
        OR SSH.detailID = 51 AND SSH.ValueID IN(88,89,145)
        AND SSH.detailID IN(52,53,98,99,100,101,106,107,108,109) AND CONVERT(VARCHAR(MAX), SSH.Value) = 'Yes'

    GROUP BY
        e.patientID
) SmokeCounselMaxDate on SmokeCounselMaxDate.patientid = u.uid

Answer 1

从此位删除括号：

INNER JOIN (structdatadetail SDD ON SSH.catid = SDD.catid      
            AND     SSH.itemid = SDD.itemid 
            AND   SSH.detailid = SDD.id)

Answer 2

检查一下，我删除了表structdatadetail的括号

左联接（选择 MAX（e.date）作为MaxDate ，e.patientID 从实验室数据内部连接enc e on e.encounterID = ld.EncounterId 和e.deleteFlag = 0 和ld.deleteFlag = 0 和ld.futureflag = 0 并且ld.cancelled = 0 并且ld.received = 1 内部联接@患者t上的t.patientID = e。PatientID SSH上的内部连接structsocialhistory SSH.encounterId = e.encounterID 内连接structdatadetail SDD ON SSH.catid = SDD.catid
AND SSH.itemid = SDD.itemid AND SSH.detailid = SDD.id SSH.catid = 10619 AND SSH.itemid = 318681 AND SSH.detailID = 49 AND SSH.ValueID = 82 或SSH.detailID = 51 AND SSH.ValueID IN（88,89,145） AND SSH.detailID IN（52,53,98,99,100,101,106,107,108,109）AND CONVERT（VARCHAR（MAX），SSH.Value）='是'

GROUP BY
    e.patientID

）SmokeCounselMaxDate.patientid = u.uid上的SmokeCounselMaxDate

消息156，级别15，状态1，行2493关键字“ ON”附近的语法错误

2 个答案: