我遇到了以下问题:如果当前正在读取文件,则可以使用wait()和notify()在文件上进行写操作,反之亦然。我试图提出一个解决方案,但是在第一次读取程序后,仅执行写操作并被卡住。这是代码
public static boolean LOCK = false;
public synchronized void read() {
String path = "/path/to/file/working.txt";
while (LOCK == true) {
try {
System.out.println("reading paused..");
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
try (BufferedReader bin = new BufferedReader(new FileReader(path))) {
LOCK = true;
String line = "";
System.out.println("reading now..");
while ((line = bin.readLine()) != null) {
System.out.println(line);
}
LOCK = false;
notify();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
public synchronized void write(String word) {
String path = "/path/to/file/working.txt";
while (LOCK == true) {
try {
System.out.println("writing paused..");
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
try (PrintWriter out = new PrintWriter(new BufferedWriter(new FileWriter(path, true)))) {
System.out.println("writing resumed..");
LOCK = true;
out.println(word);
LOCK = false;
notify();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
我通过了一个水果的String数组作为测试,将read()和write()作为单独的线程启动,并且我得到的输出是
Writing resumed..
reading..
Apple
Writing resumed..
Writing resumed..
Writing resumed..
输出被完全写入,但是在第一个字之后没有读取操作发生。请您告诉我我做错了什么吗?谢谢。
这是测试代码,
String[] fruits = { "Apple", "Banana", "Orange", "Cherry", "Date", "ElderBerry", "Marionberry", "Blueberry", };
FileSyncDemo fileDemo = new FileSyncDemo();
Runnable r = () -> {
try {
fileDemo.read();
Thread.sleep((long) (Math.random() * 1000));
} catch (InterruptedException e) {
e.printStackTrace();
}
};
Runnable r2 = () -> {
try {
for (int i = 0; i < fruits.length; i++) {
fileDemo.write(fruits[i]);
Thread.sleep((long) (Math.random() * 1000));
}
} catch (InterruptedException e) {
e.printStackTrace();
}
};
Thread t = new Thread(r);
t.start();
Thread t2 = new Thread(r2);
t2.start();
}