Question

CREATE TABLE Subject_Marks
(   
    Marks_ID int primary key,
    Maths_Score int,
    Science_Score int,
    Social_Score int,
    English_Score int,
    SUPW_Score int,
    Student_ID int  not null

    );

INSERT into Subject_Marks VALUES
(1,1001, 50, 99,98,45,57);

无法将此表与下面显示的其他表联接。

CREATE TABLE Student_Data
(   
    Student_ID int IDENTITY(1001,1) PRIMARY KEY,
    Student_Name VARCHAR(20) NOT NULL,
    Student_Address VARCHAR(100),
    Student_Phone bigint,
    Student_Email VARCHAR(30),
    college_id int NOT NULL
);

Answer 1

由于Student_ID是提供关系的键，因此需要在联接中使用它。因此，您需要为SQL Server构建如下所示的联接：

select sd.* , sm.*
from Student_Data sd
inner join Subject_Marks sm on sm.Student_ID = sd.Student_ID

无效的对象名称'Subject_Marks'

1 个答案: