基本上我想遍历数据库中的所有0,然后再开始遍历2。
查询为:
SELECT IP,Time,HostName
FROM RoughScan
CASE WHEN EXISTS (DeepScan=0)
THEN (DeepScan=0 LIMIT 1)
ELSE (DeepScan=2 LIMIT 1)
但我收到错误消息:
CASE表达式的意外结尾(位置“ 0”附近的“”附近)
我也在使用MariaDB服务器。
答案 0 :(得分:0)
如果每种类型都需要一行,请使用window.CKEDITOR.on('dialogDefinition', function (ev) {
var dialogName = ev.data.name;
var dialogDefinition = ev.data.definition;
ev.editor.getCommand( 'table' ).allowedContent = "table{width,height}[align,border,cellpadding,cellspacing,summary];caption tbody thead tfoot;th td tr;table[id,dir](*){*}";
if (dialogName == "table" && dialogName == "tableProperties") {
var infoTab = dialogDefinition.getContents("info");
infoTab.get("txtWidth")["default"] = "";
infoTab.get("txtCellSpace")["default"] = "";
infoTab.get("txtCellPad")["default"] = "";
infoTab.get("txtBorder")["default"] = "";
infoTab.get("selHeaders")["items"].pop();
infoTab.get("selHeaders")["items"].pop();
var advancedTab = dialogDefinition.getContents( 'advanced' );
advancedTab.remove( 'advCSSClasses' );
}
});
:
union all
请注意,(SELECT `IP`,`Time`,`HostName`
FROM `RoughScan`
WHERE DeepScan = 0
LIMIT 1
)
UNION ALL
(SELECT `IP`,`Time`,`HostName`
FROM `RoughScan`
WHERE DeepScan = 2
LIMIT 1
);
通常与ORDER BY
一起使用。
答案 1 :(得分:0)
您需要像这样将CASE应用于WHERE:
SELECT IP,Time,HostName
FROM RoughScan
WHERE
DeepScan = CASE
WHEN EXISTS (SELECT 1 FROM RoughScan WHERE DeepScan = 0) THEN 0
ELSE 2
END
LIMIT 1