在JavaScript中对数组的索引进行排序

时间：2019-02-01 11:45:57

标签： javascript vue.js ecmascript-6 vuejs2

我正在尝试在Vuejs上构建一个小型应用程序，在那里我拥有一组通过api响应提供的数组，该数组给出以下输出：

{
    "data":
    {
        "Real Estate Regulatory Act":[
            {
                "id":603,
                "project_id":2392,
                "parent_type":"Real Estate Regulatory Act",
                "type":"Building Plan Approval",
                "name":"FORMS.pdf",
                "link":"https://.....DyumatHotelsFORMS.pdf"
            }
        ],
        "Environmental Clearance":[
            {
                "id":602,
                "project_id":2392,
                "parent_type":"Environmental Clearance",
                "type":"Form 1",
                "name":"HotelsCPEMP.pdf",
                "link":"https://.....MarineandDyumatHotelsCPEMP.pdf"
            }
        ],
        "Document":[
            {
                "id":601,
                "project_id":2392,
                "parent_type":"Document",
                "type":"Land Details",
                "name":"FORMS.pdf",
                "link":"https://....HotelsFORMS.pdf"
            }
        ],
        "Miscellaneous Approvals":[
            {
                "id":604,
                "project_id":2392,
                "parent_type":
                "Miscellaneous Approvals",
                "type":"Not Reported",
                "name":"Report Part 1.pdf",
                "link":"https://...Report Part 1.pdf"
            }
        ]
    }
}

我要根据以下数组的索引对这个javascript进行排序：

['Document', 'Environmental Clearance', 'Real Estate Regulatory Act', 'Miscellaneous Approvals']

所以我的最终结果将是：

{
    "data":
    {
        "Document":[
            {
                "id":601,
                "project_id":2392,
                "parent_type":"Document",
                "type":"Land Details",
                "name":"FORMS.pdf",
                "link":"https://....HotelsFORMS.pdf"
            }
        ],
        "Environmental Clearance":[
            {
                "id":602,
                "project_id":2392,
                "parent_type":"Environmental Clearance",
                "type":"Form 1",
                "name":"HotelsCPEMP.pdf",
                "link":"https://.....MarineandDyumatHotelsCPEMP.pdf"
            }
        ],
        "Real Estate Regulatory Act":[
            {
                "id":603,
                "project_id":2392,
                "parent_type":"Real Estate Regulatory Act",
                "type":"Building Plan Approval",
                "name":"FORMS.pdf",
                "link":"https://.....DyumatHotelsFORMS.pdf"
            }
        ],
        "Miscellaneous Approvals":[
            {
                "id":604,
                "project_id":2392,
                "parent_type":
                "Miscellaneous Approvals",
                "type":"Not Reported",
                "name":"Report Part 1.pdf",
                "link":"https://...Report Part 1.pdf"
            }
        ]
    }
}

我的代码当前如下所示：

if(response.status === 200)
{
    let docs = response.data.data;
    let sortDocs = ['Document', 'Environmental Clearance', 'Real Estate Regulatory Act', 'Miscellaneous Approvals'];
    let result = []

    sortDocs.forEach(function(key) {
        this.subscProDocument[key] = result.push(docs[key])
    })

}

我遇到类似这样的错误：

  

未捕获（承诺）TypeError：无法读取未定义的属性'subscProDocument'

我已经在data（）中定义了这个subscProDocument并初始化为一个空数组。帮我解决这个问题。谢谢

5 个答案:

答案 0 :(得分：1)

let data = {
    "data":
    {
        "Real Estate Regulatory Act":[
            {
                "id":603,
                "project_id":2392,
                "parent_type":"Real Estate Regulatory Act",
                "type":"Building Plan Approval",
                "name":"FORMS.pdf",
                "link":"https://.....DyumatHotelsFORMS.pdf"
            }
        ],
        "Environmental Clearance":[
            {
                "id":602,
                "project_id":2392,
                "parent_type":"Environmental Clearance",
                "type":"Form 1",
                "name":"HotelsCPEMP.pdf",
                "link":"https://.....MarineandDyumatHotelsCPEMP.pdf"
            }
        ],
        "Document":[
            {
                "id":601,
                "project_id":2392,
                "parent_type":"Document",
                "type":"Land Details",
                "name":"FORMS.pdf",
                "link":"https://....HotelsFORMS.pdf"
            }
        ],
        "Miscellaneous Approvals":[
            {
                "id":604,
                "project_id":2392,
                "parent_type":
                "Miscellaneous Approvals",
                "type":"Not Reported",
                "name":"Report Part 1.pdf",
                "link":"https://...Report Part 1.pdf"
            }
        ]
    }
};

从对象获取数据并分配给unordered变量 

const unordered = data.data;

声明新变量ordered 

const ordered = {};

Object.keys将从keys获取unordered object的数组，然后将sort function应用于ascending sort的键。

然后我们将在forEach上执行array of keys循环，并将带有键的值分配给ordered object; 

Object.keys(unordered).sort().forEach(function(key) {
  ordered[key] = unordered[key];
});

console.log(ordered);

答案 1 :(得分：0)

这是解决方案：

var obj={
    "data":
    {
        "Real Estate Regulatory Act":[
            {
                "id":603,
                "project_id":2392,
                "parent_type":"Real Estate Regulatory Act",
                "type":"Building Plan Approval",
                "name":"FORMS.pdf",
                "link":"https://.....DyumatHotelsFORMS.pdf"
            }
        ],
        "Environmental Clearance":[
            {
                "id":602,
                "project_id":2392,
                "parent_type":"Environmental Clearance",
                "type":"Form 1",
                "name":"HotelsCPEMP.pdf",
                "link":"https://.....MarineandDyumatHotelsCPEMP.pdf"
            }
        ],
        "Document":[
            {
                "id":601,
                "project_id":2392,
                "parent_type":"Document",
                "type":"Land Details",
                "name":"FORMS.pdf",
                "link":"https://....HotelsFORMS.pdf"
            }
        ],
        "Miscellaneous Approvals":[
            {
                "id":604,
                "project_id":2392,
                "parent_type":
                "Miscellaneous Approvals",
                "type":"Not Reported",
                "name":"Report Part 1.pdf",
                "link":"https://...Report Part 1.pdf"
            }
        ]
    }
};

function map(it){
   var item={};
   item[it]=obj.data[it];
   return item;
}

console.log(Object.keys(obj.data).sort().map(map));

答案 2 :(得分：0)

您的data.data对象如果要订购其项目，应为数组，因为您不能依赖Object中键的顺序，因为它是不保证。 这是post about key ordering in JS objects

您可以执行以下排序并转换为一行的数组：

data.data = orderedKeys.map(key => ({ [key]: data.data[key] }));

这将为您提供：

{
  "data": [
  {
      "Document": [{
          "id": 601,
          "project_id": 2392,
          ...
        }]
    },
    {
      "Environmental Clearance": [{
          "id": 602,
          "project_id": 2392,
          ...
        }]
    },
    {
      "Real Estate Regulatory Act": [{
          "id": 603,
          "project_id": 2392,
          ...
        }]
    },
    {
      "Miscellaneous Approvals": [{
          "id": 604,
          "project_id": 2392,
          ...
        }]
    }
  ]
}

这是一个有效的示例： 

const data = {
    "data": {
        "Real Estate Regulatory Act": [{
            "id":603,
            "project_id":2392,
            "parent_type":"Real Estate Regulatory Act",
            "type":"Building Plan Approval",
            "name":"FORMS.pdf",
            "link":"https://.....DyumatHotelsFORMS.pdf"
        }],
        "Environmental Clearance": [{
            "id":602,
            "project_id":2392,
            "parent_type":"Environmental Clearance",
            "type":"Form 1",
            "name":"HotelsCPEMP.pdf",
            "link":"https://.....MarineandDyumatHotelsCPEMP.pdf"
        }],
        "Document": [{
            "id":601,
            "project_id":2392,
            "parent_type":"Document",
            "type":"Land Details",
            "name":"FORMS.pdf",
            "link":"https://....HotelsFORMS.pdf"
        }],
        "Miscellaneous Approvals": [{
            "id":604,
            "project_id":2392,
            "parent_type":
            "Miscellaneous Approvals",
            "type":"Not Reported",
            "name":"Report Part 1.pdf",
            "link":"https://...Report Part 1.pdf"
        }]
    }
};

const orderedKeys = ['Document', 'Environmental Clearance', 'Real Estate Regulatory Act', 'Miscellaneous Approvals'];

data.data = orderedKeys.map(key => ({ [key]: data.data[key] }));

console.log(data)

答案 3 :(得分：0)

您需要以Array#forEach的this身份引用thisArg 

sortDocs.forEach(function(key) {
    this.subscProDocument[key] = result.push(docs[key]);
}, this);

或采用一个arrow function，它占用了外部范围的this。

sortDocs.forEach(key => this.subscProDocument[key] = result.push(docs[key]));

答案 4 :(得分：0)

let obj = {
    "data":
    {
        "Real Estate Regulatory Act":[
            {
                "id":603,
                "project_id":2392,
                "parent_type":"Real Estate Regulatory Act",
                "type":"Building Plan Approval",
                "name":"FORMS.pdf",
                "link":"https://.....DyumatHotelsFORMS.pdf"
            }
        ],
        "Environmental Clearance":[
            {
                "id":602,
                "project_id":2392,
                "parent_type":"Environmental Clearance",
                "type":"Form 1",
                "name":"HotelsCPEMP.pdf",
                "link":"https://.....MarineandDyumatHotelsCPEMP.pdf"
            }
        ],
        "Document":[
            {
                "id":601,
                "project_id":2392,
                "parent_type":"Document",
                "type":"Land Details",
                "name":"FORMS.pdf",
                "link":"https://....HotelsFORMS.pdf"
            }
        ],
        "Miscellaneous Approvals":[
            {
                "id":604,
                "project_id":2392,
                "parent_type":
                "Miscellaneous Approvals",
                "type":"Not Reported",
                "name":"Report Part 1.pdf",
                "link":"https://...Report Part 1.pdf"
            }
        ]
    }
};

const orderedObj = { data: {} };
Object.keys(obj.data).sort().forEach(function(key) {
  orderedObj.data[key] = obj.data[key];
});
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