Question

我是使用查询生成器的新手，今天我停留在查询生成器上。我试图做名称列也要多选。这是我要转换查询生成器的内容：

SELECT 
users.name,
users.surname,
users.avatar_path,
users.city_id,
users.district_id,
users.neighboor_id,
cities.name as city_name
FROM users,cities
WHERE users.city_id = cities.id
AND users.name LIKE 'bar%'

没有使用 DB :: raw（）吗？

谢谢。

Answer 1

在此处使用join query

DB::table('users')
     ->select('users.name','users.surname','users.avatar_path','users.city_id','users.district_id','users.neighboor_id','cities.name as city_name')
     ->join('users','users.city_id','=','cities.id')
     ->where('users.name','LIKE',$searchText.'%')   //add here your variable
     ->get();

Laravel查询生成器多个选择和命名列

1 个答案: