let array = [
{id: "455", some: [{id: "21"}]},
{id: "12", some: [{id: "21"}]},
{id: "12", some: [{id: "21"}]}
];
array.slice("some");
在这里,我试图删除数组中的一个数组,但是它不起作用。
在这里,我只想从所有对象中删除some
数组。
答案 0 :(得分:2)
您可以使用rest语法和一些Object Destructuring:
let result = array.map(({ some, ...rest}) => rest);
演示:
let array = [
{id: "455", some: [{id: "21"}]},
{id: "12", some: [{id: "21"}]},
{id: "12", some: [{id: "21"}]}
];
let result = array.map(({ some, ...rest}) => rest);
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
答案 1 :(得分:2)
一行:
let array = [{id:"455",some:[{id:"21",},],},{id:"12",some:[{id:"21",},],},{id:"12",some:[{id:"21",},],}];
array.forEach(it => delete it.some);
console.log(array);
答案 2 :(得分:1)
您可以使用map和destructuring仅取出所需的属性和值。
let array = [{id:"455",some:[{id:"21",},],},{id:"12",some:[{id:"21",},],},{id:"12",some:[{id:"21",},],}];
let result = array.map(({id}) => ({id}));
console.log(result);