Question

我将自己的sql更改为hql，在sql中我有此

CASE `Leave_Type`
    WHEN 1 THEN IF(STRCMP(`Leave_Comments`,'') = 0, 'Annual Leave', concat('Annual Leave: ', `Leave_Comments`))
    WHEN 2 THEN IF(STRCMP(`Leave_Comments`,'') = 0, 'Sick Leave', concat('Sick Leave: ', `Leave_Comments`))
    WHEN 3 THEN IF(STRCMP(`Leave_Comments`,'') = 0, 'Maternity/Paternity Leave', concat('Maternity/Paternity Leave: ', `Leave_Comments`))
    WHEN 4 THEN IF(STRCMP(`Leave_Comments`,'') = 0, 'Family Leave', concat('Family Leave: ', `Leave_Comments`))
    WHEN 5 THEN IF(STRCMP(`Leave_Comments`,'') = 0, 'Study Leave', concat('Study Leave: ', `Leave_Comments`))
    WHEN 6 THEN IF(STRCMP(`Leave_Comments`,'') = 0, 'Unpaid Leave', concat('Unpaid Leave: ', `Leave_Comments`))
    WHEN 7 THEN IF(STRCMP(`Leave_Comments`,'') = 0, 'Other Leave', concat('Other Leave: ', `Leave_Comments`))
END As 'text',

我尝试通过以下尝试将其移植到hql，但出现错误

org.hibernate.hql.internal.ast.QuerySyntaxException: expecting \"end\", found 'else' near line 1, column 594

像这样的sql，正确的hql等效项是什么？

HQL尝试：

(case when l.leave_Type = 1 then (case when strcmp(l.leave_Comments,'') = 0 then 'Annual Leave' else concat('Annual Leave: ', l.leave_Comments) else 
(case when l.leave_Type = 2 then (case when strcmp(l.leave_Comments,'') = 0 then 'Sick Leave' else concat('Annual Leave: ', l.leave_Comments) end) else 
(case when l.leave_Type = 3 then (case when strcmp(l.leave_Comments,'') = 0 then 'Maternity/Paternity Leave' else concat('Maternity/Paternity Leave: ', l.leave_Comments) end) else 
(case when l.leave_Type = 4 then (case when strcmp(l.leave_Comments,'') = 0 then 'Family Leave' else concat('Family Leave: ', l.leave_Comments) end) else 
(case when l.leave_Type = 5 then (case when strcmp(l.leave_Comments,'') = 0 then 'Study Leave' else concat('Study Leave: ', l.leave_Comments) end) else 
(case when l.leave_Type = 6 then (case when strcmp(l.leave_Comments,'') = 0 then 'Unpaid Leave' else concat('UnpaidLeave: ', l.leave_Comments) end) else 
(case when l.leave_Type = 7 then (case when strcmp(l.leave_Comments,'') = 0 then 'Other Leave' else concat('Other Leave: ', l.leave_Comments) end) else null end) end) end) end) end)) end) end)

Answer 1

case when l.leave_Type = 1 then 
    (case when strcmp(l.leave_Comments,'') = 0 then 'Annual Leave' else concat('Annual Leave: ', l.leave_Comments)  end)
when l.leave_Type = 2 then 
    (case when strcmp(l.leave_Comments,'') = 0 then 'Sick Leave' else concat('Annual Leave: ', l.leave_Comments) end) 
when l.leave_Type = 3 then 
    (case when strcmp(l.leave_Comments,'') = 0 then 'Maternity/Paternity Leave' else concat('Maternity/Paternity Leave: ', l.leave_Comments) end) 
when l.leave_Type = 4 then 
    (case when strcmp(l.leave_Comments,'') = 0 then 'Family Leave' else concat('Family Leave: ', l.leave_Comments) end) 
when l.leave_Type = 5 then 
    (case when strcmp(l.leave_Comments,'') = 0 then 'Study Leave' else concat('Study Leave: ', l.leave_Comments) end) 
when l.leave_Type = 6 then 
    (case when strcmp(l.leave_Comments,'') = 0 then 'Unpaid Leave' else concat('UnpaidLeave: ', l.leave_Comments) end) 
when l.leave_Type = 7 then 
    (case when strcmp(l.leave_Comments,'') = 0 then 'Other Leave' else concat('Other Leave: ', l.leave_Comments) end) 
else NULL end

相同属性的Hibernate HQL多案例语句

1 个答案: