我正尝试将Json转换为Java对象。我有一个名为' result '的字符串,我想将其转换为类为 TransferRecord.java < / strong>
这是我用作输入的字符串的一部分。
{
"TransferRecord": {
"TransferId": {
"TransferRef": "string",
"DistributorRef": "string"
},
"SkuCode": "string",
"Price": {
"CustomerFee": 0,
"DistributorFee": 0,
"ReceiveValue": 0,
"ReceiveCurrencyIso": "string",
"ReceiveValueExcludingTax": 0,
"TaxRate": 0,
"TaxName": "string",
"TaxCalculation": "string",
"SendValue": 0,
"SendCurrencyIso": "string"
},
"CommissionApplied": 0,
"StartedUtc": "2019-01-31T10:10:20.527Z",
"CompletedUtc": "2019-01-31T10:10:20.527Z",
"ProcessingState": "string",
"ReceiptText": "string",
"ReceiptParams": {},
"AccountNumber": "string"
},
"ResultCode": 0,
"ErrorCodes": [
{
"Code": "string",
"Context": "string"
}
]
}
这是TransferRecord类。我检查了json映射,它们完全相同。请注意,类中有更多字段可用,但我只是粘贴了一部分。输入字符串和java类的属性数相同。
public class TransferRecord {
@JsonProperty("TransferId")
private TransferId transferId = null;
@JsonProperty("SkuCode")
private String skuCode = null;
@JsonProperty("Price")
private Price price = null;
@JsonProperty("CommissionApplied")
private BigDecimal commissionApplied = null;
@JsonProperty("StartedUtc")
private Date startedUtc = null;
@JsonProperty("CompletedUtc")
private Date completedUtc = null;
@JsonProperty("ProcessingState")
private String processingState = null;
@JsonProperty("ReceiptText")
private String receiptText = null;
@JsonProperty("ReceiptParams")
private Map<String, String> receiptParams = null;
@JsonProperty("AccountNumber")
private String accountNumber = null;
public TransferRecord transferId(TransferId transferId) {
this.transferId = transferId;
return this;
}
}
以下是我用于转换的代码。请注意,这三段代码将达到相同的目的,因此我分别进行了尝试。
ObjectMapper mapper = new ObjectMapper();
//1 TransferRecord objTransRecord = mapper.readValue(result, TransferRecord.class);
//2 TransferRecord objTransRecord = mapper.readerWithView(TransferRecord.class).forType(TransferRecord.class).readValue(result);
//3 TransferRecord objTransRecord = mapper.readerFor(TransferRecord.class).readValue(result);
问题是当我尝试创建对象时,即使String中有相应的数据,在所有三种方法中,每个值都设置为 null 。有人可以指出我在这里做错了吗?
先谢谢了。 :)
答案 0 :(得分:2)
首先,json应该是:
{
"TransferId": {
"TransferRef": "string",
"DistributorRef": "string"
},
"SkuCode": "string",
"Price": {
"CustomerFee": 0,
"DistributorFee": 0,
"ReceiveValue": 0,
"ReceiveCurrencyIso": "string",
"ReceiveValueExcludingTax": 0,
"TaxRate": 0,
"TaxName": "string",
"TaxCalculation": "string",
"SendValue": 0,
"SendCurrencyIso": "string"
},
"CommissionApplied": 0,
"StartedUtc": "2019-01-31T10:10:20.527Z",
"CompletedUtc": "2019-01-31T10:10:20.527Z",
"ProcessingState": "string",
"ReceiptText": "string",
"ReceiptParams": {},
"AccountNumber": "string"
}
第二,也许您应该为每个字段添加getter和setter方法。
答案 1 :(得分:2)
使用toString方法直接打印值并按如下所示构造类
ObjectMapper mapper = new ObjectMapper();
Data data = mapper.readValue(string, Data.class);
System.out.println(data);
数据类
public class Data {
@JsonProperty("TransferRecord")
private TransferRecord transferRecord;
@JsonProperty("ResultCode")
private int
resultCode;
@JsonProperty("ErrorCodes")
private List<ErrorCode> errorCodes;
@Override
public String toString() {
return "Data [transferRecord=" + transferRecord + ", resultCode=" + resultCode + ", errorCodes=" + errorCodes
+ "]";
}
}
错误代码类别:
public class ErrorCode {
@JsonProperty("Code")
private String code;
@JsonProperty("Context")
private String context;
@Override
public String toString() {
return "ErrorCode [code=" + code + ", context=" + context + "]";
}
}
TransferRecord类:
public class TransferRecord {
@JsonProperty("TransferId")
private TransferId transferId;
@JsonProperty("SkuCode")
private String skuCode;
@JsonProperty("Price")
private Price price;
@JsonProperty("CommissionApplied")
private BigDecimal commissionApplied;
@JsonProperty("StartedUtc")
private Date startedUtc;
@JsonProperty("CompletedUtc")
private Date completedUtc;
@JsonProperty("ProcessingState")
private String processingState;
@JsonProperty("ReceiptText")
private String receiptText;
@JsonProperty("ReceiptParams")
private Map<String, String> receiptParams;
@JsonProperty("AccountNumber")
private String accountNumber;
@Override
public String toString() {
return "TransferRecord [transferId=" + transferId + ", skuCode=" + skuCode + ", price=" + price
+ ", commissionApplied=" + commissionApplied + ", startedUtc=" + startedUtc + ", completedUtc="
+ completedUtc + ", processingState=" + processingState + ", receiptText=" + receiptText
+ ", receiptParams=" + receiptParams + ", accountNumber=" + accountNumber + "]";
}
}
TransferId类别:
public class TransferId {
@JsonProperty("TransferRef")
private String transferRef;
@JsonProperty("DistributorRef")
private String distributorRef;
@Override
public String toString() {
return "TransferId [transferRef=" + transferRef + ", distributorRef=" + distributorRef + "]";
}
}
价格等级:
public class Price {
@JsonProperty("CustomerFee")
private int customerFee;
@JsonProperty("DistributorFee")
private int distributorFee;
@JsonProperty("ReceiveValue")
private int receiveValue;
@JsonProperty("ReceiveCurrencyIso")
private String receiveCurrencyIso;
@JsonProperty("ReceiveValueExcludingTax")
private int receiveValueExcludingTax;
@JsonProperty("TaxRate")
private int taxRate;
@JsonProperty("TaxName")
private String taxName;
@JsonProperty("TaxCalculation")
private String taxCalculation;
@JsonProperty("SendValue")
private int sendValue;
@JsonProperty("SendCurrencyIso")
private String sendCurrencyIso;
@Override
public String toString() {
return "Price [customerFee=" + customerFee + ", distributorFee=" + distributorFee + ", receiveValue="
+ receiveValue + ", receiveCurrencyIso=" + receiveCurrencyIso + ", receiveValueExcludingTax="
+ receiveValueExcludingTax + ", taxRate=" + taxRate + ", taxName=" + taxName + ", taxCalculation="
+ taxCalculation + ", sendValue=" + sendValue + ", sendCurrencyIso=" + sendCurrencyIso + "]";
}
}
答案 2 :(得分:1)
这不是TransferRecord类。您的json提取类包含3个字段:
public class Something {
@JsonProperty("TransferRecord")
private TransferRecord transferRecord;
@JsonProperty("ResultCode")
private int resultCode;
@JsonProperty("ErrorCodes")
private List<ErrorCode> errorCodes;
}