如何仅从原型函数中获取参数值

Question

下面是我的构造函数“ Req”和原型函数“ get”来发出http请求。

var request = require('request');

function Req(url, type, body) {
	this.url = url;
	this.username = "##############";
	this.password = "##############";
	this.type = type;
	this.body = body
	this.authenticationHeader = "Basic " + new Buffer(this.username + ":" + this.password).toString("base64");
}


Req.prototype.get = function (callback) {

	request(
		{
			url: this.url,
			headers: { "Authorization": this.authenticationHeader }
		},
		function (error, response, body) {
			if (error) {
				console.log("Error in Get Request is " + error)
			}
			else if (body) {
		    console.log("******************GET Response is****************" + "\n" + body)
			}

			callback();
		}
	);
}

这工作正常，我在Cucumber

中这样调用此原型函数

var testObject;

Given('I have request with {string}, {string} and {string}', function (url, type, body) {
	testObject = new Req(url, type, body)


});
When('the request is triggered', function (callback) {
		testObject.get(callback);
})

但是我只想显示The Step中的“ Body”响应值

Then('I should get the result', function () {
 How to do here??
});
    

感谢您的帮助。

Answer 1

将error和body的值传递到回调中，以便可以看到这些值。

Req.prototype.get = function(callback) {
    request({
            url: this.url,
            headers: {
                "Authorization": this.authenticationHeader
            }
        }, function(error, response, body) {
            if (error) {
                console.log("Error in Get Request is " + error)
                callback(error);
            } else {
                console.log("******************GET Response is****************" + "\n" + body)
                callback(null, body);
            } 
        }
    );
}

someObj.get(function(err, body) {
    if (!err) {
        console.log(body);
    }
});

仅供参考，我不了解量角器和黄瓜，所以我向您展示了一种纯Javascript方式。