Question

给出一个array()，如下所示：

Array
(
    [0] => 1
    [1] => Lorem ipsum
    [2] => dolor sit
    [3] => amet
    [4] => 2
    [5] => consectetur
    [6] => adipiscing elit
    [7] => adipiscing elit
    [8] => 3
    [9] => Integer nec
    [10] => odio
)

具有一组动态数字（1，2，3，4，5等）。

实现这样的结果的一种更有效的方法是

Array
(
    [1] => Array
        (
            [0] => 1
            [1] => Lorem ipsum
            [2] => dolor sit
            [3] => amet
        )

    [2] => Array
        (
            [0] => 2
            [1] => consectetur
            [2] => adipiscing elit
            [3] => adipiscing elit
        )

    [3] => Array
        (
            [0] => 3
            [1] => Integer nec
            [2] => odio
        )

)

递增的数组值用作将数组拼接为单独的块的分割点：

（工作示例）https://3v4l.org/EqnIN

$exploded = array(
    '1',
    'Lorem ipsum',
    'dolor sit',
    'amet',
    '2',
    'consectetur',
    'adipiscing elit',
    'adipiscing elit',
    '3',
    'Integer nec',
    'odio'
);

$array = array();
$a = false;
$count = 1;
$arraycount = count($exploded);

for ($i = 0; $i < $arraycount; $i++)
    {
    $countstring = $count + 1;
    $countstring = (string)$countstring;
    if ($exploded[$i] == $count)
        {
        $array[$count][] = $exploded[$i];
        $a = true;
        }
    elseif ($a == true && $exploded[$i] == (string)$count)
        {
        $array[$count][] = $exploded[$i];
        }
    elseif ($a == true && $exploded[$i + 1] != $countstring)
        {
        $array[$count][] = $exploded[$i];
        }
    elseif ($a == true && $exploded[$i + 1] == $countstring)
        {
        $array[$count][] = $exploded[$i];
        $count++;
        $a = false;
        }
    }

Answer 1

我相信这应该等同于您的代码：

$array = array();
$count = -1;
$nextcount = 1;
$arraycount = count($exploded);

for ($i = 0; $i < $arraycount; $i++) {
    if ($exploded[$i] == $nextcount) {
        $count++;
        $nextcount++;
    }
    $array[$count][] = $exploded[$i];
}

基于增量数值的拆分数组

1 个答案: