为什么我的try-catch在捕获错误时会打印出错误和catch块?

时间:2019-02-01 03:04:08

标签: java try-catch

我目前正在学习try-catch代码块,并且正在编写一段代码,该代码从用户处获取输入并检查其是否为整数。我的代码是

int classSize = 0;
boolean error = false;
    do {
        try{
            System.out.println("Hello! Please enter how many Students you have in your class: ");
            classSize = in.nextInt();
            error = false;
        }
        catch(InputMismatchException e){
            System.out.println("Invalid input. please make sure you enter numbers ONLY! No symbols or letters.");
            classSize = in.nextInt();
            error = true;
        }
    }while(error);

当我尝试通过输入字母进行测试时,我同时收到错误消息和try阻止消息。

Hello! Please enter how many Students you have in your class: 
asdfsda

Invalid input. please make sure you enter numbers ONLY! No symbols or 
letters.

Exception in thread "main" java.util.InputMismatchException
at java.base/java.util.Scanner.throwFor(Scanner.java:939)
at java.base/java.util.Scanner.next(Scanner.java:1594)
at java.base/java.util.Scanner.nextInt(Scanner.java:2258)
at java.base/java.util.Scanner.nextInt(Scanner.java:2212)
at ExcerciseOne.main(ExcerciseOne.java:65)

为什么显示catch块和错误消息?我是否正确使用try-catch块?

3 个答案:

答案 0 :(得分:3)

您正在捕获$school->ratings->status 子句中引发的异常,但是随后您再次从try内部的扫描程序中读取并因此引发了另一个未捕获的异常。

catch

在两个子句中都存在,两次都抛出异常,但是只有从classSize = in.nextInt(); 子句内部抛出时才会被捕获。

答案 1 :(得分:1)

in.nextInt()块中进行的catch调用读取在in.nextInt()块中对try的第一次调用留下的不良流。

您可以做的是删除.nextInt()块中的catch个调用:

boolean hasError = true;
while (hasError) {
    try {
        System.out.println("Hello! Please enter how many Students you have in your class: ");
        classSize = in.nextInt();
        hasError = false;
    } catch (InputMismatchException e) {
        System.out.println("Invalid input. please make sure you enter numbers ONLY! No symbols or letters.");
        // variable has error remains true
    }
}

或更佳:

由于InputMismatchExceptionRuntimeException的子类,因此可以通过if语句过滤掉引发此错误的错误类型。由于只需要一个适当的整数作为输入,因此可以使用正则表达式来验证输入。

boolean hasError = true;
String integerRegex = "[\\d]+"; // it means 1-to-many digits
while (hasError) {
    System.out.println("Hello! Please enter how many Students you have in your class: ");
    String input = in.nextLine();
    if (input.matches(integerRegex)) {
        classSize = Integer.parseInt(input);
        hasError = false;
    } else {
        System.out.println("Invalid input. please make sure you enter numbers ONLY! No symbols or letters.");
        // variable hasError remains true
    }
}

答案 2 :(得分:1)

Gendarme的答案很明确,我为您添加了一个正确的演示:

  public static void main(String[] args) {
      int studentsCount = 0;
      boolean hasError;
      do {
        try {
          System.out.println("Hello! Please enter how many Students you have in your class: ");
          Scanner in = new Scanner(System.in);
          studentsCount = in.nextInt();
          hasError = false;
        } catch (InputMismatchException e) {
          System.out.println("--> Invalid input. please make sure you enter numbers ONLY! No symbols or letters.");
          hasError = true;
        }
      } while (hasError);
      System.out.println("There are " + studentsCount + " students in your class.");
  }