Question

我目前正在尝试通过将日期转换为时间戳来在数据集中生成数字特征。如果在Mac上运行，它将完美运行，在Windows上抛出

OS Error: [Errno 22] Invalid argument

这可能是由于窗口not supporting unix timestamps from before 1970-01-01造成的。我的约会从1955年开始。这是我的代码：

import time
import datetime

current_timestamp = time.time()
df.loc[:, "FEATURE_num"] = df["FEATURE"].apply(lambda d: datetime.datetime.strptime(d, '%Y-%m-%d').timestamp() if isinstance(d, str) else current_timestamp)

我在某处看到建议使用datetime.timedelta()，但我不知道如何集成它。

Answer 1

您可以通过（隐式）使用datetime.timedelta来计算“格里高利”时间戳，该时间戳对1582年10月15日至今的日期（或您想要的其他“时代”）有效使用）。

from datetime import datetime


GREGORIAN_EPOCH = datetime.strptime('1582-10-15', '%Y-%m-%d')


def gregorian_timestamp(date, format='%Y-%m-%d'):
    """ Calculate timestamp using start of Gregorian calender as epoch.

        The date parameter can be either be a string or a datetime.datetime
        object. Strings will be parsed using the '%Y-%m-%d' format by default
        unless a different one is specfied via the optional format parameter.
    """
    try:
        date = datetime.strptime(date, format)
    except TypeError:
        pass
    return (date - GREGORIAN_EPOCH).total_seconds()  # The timedelta in seconds.


if __name__ == '__main__':

    current_date = datetime.now()
    timestamp = gregorian_timestamp(current_date)
    print('gregorian timestamp:', timestamp)  # -> gregorian timestamp: 13768250461.136208

    timestamp = gregorian_timestamp('1970-01-01')
    print('gregorian timestamp:', timestamp)  # -> gregorian timestamp: 12219292800.0

    timestamp = gregorian_timestamp('1955-02-28')
    print('gregorian timestamp:', timestamp)  # -> gregorian timestamp: 11750918400.0

    timestamp = gregorian_timestamp('1582-10-15')
    print('gregorian timestamp:', timestamp)  # -> gregorian timestamp: 0.0

Windows上日期为1970-01-01之前的datetime timestamp（）的变通办法

1 个答案: