Question

此代码之前工作正常，但是现在我遇到了while 0 <= int（relationship）> 3代码块的问题。用户应该能够选择与信件接收者的关系类型，这将把称呼和称呼填充到信件中。

如果我将if / elif语句保留在while循环中，则sal / val字符串不会填充到字母中。

如果使if / elif语句与while循环齐平，则仅当用户第一次键入1、2或3时，字符串才会填充字母。如果用户键入的数字不是1、2或3，则程序将继续执行，但不会填充sal / val字符串。

最初，我只有一组if / elif语句，但是我创建了两组（这是多余的，并且也没有解决问题）语句，以查看是否可以解决问题。我也弄乱了缩进。我还尝试为每种类型的关系创建函数，但我不断因称呼而出现名称错误。

如果用户第一次遵循指示，我可以使该程序正常运行；如果在第一次尝试时出现错误，提示用户键入1、2或3，则可以使该程序运行。但是在两种情况下我都无法填充sal / val。我觉得问题一定与缩进有关，但是当我更改缩进级别时，问题并没有解决。

# Function for an infinite nested dictionary to add content to a personalized letter 
def lkng_glss_lttr_bot():             

    lgl_num = 0 
    while command == 'compose': 

        store_lkng_glss_lttr = {}
        new_lgl = {} 
        new_lgl_num = len(store_lkng_glss_lttr) + 1 
        store_lkng_glss_lttr[new_lgl_num] = new_lgl

        address_acquaintence = ['Dear', 'Cordially,']
        address_friend = ['Dearest', 'With warmest regards,']
        address_beloved = ['My Darling', 'With all my love and affection,']
        salutation = ''
        valediction = ''

        recipient = input("\nWhat is the recipient’s name?\n") 
        new_lgl['recipient'] = recipient

        email = input("\nWhat is the recipient's email?\n")
        new_lgl['email'] = email


        print("\nWhat is your relationship to %s?" % recipient)
        relationship = int(input("""Type 1 for Acquaintence
    Type 2 for Friend
    Type 3 for Beloved\n"""))

        while 0 <= int(relationship) > 3:
            relationship = input("Please type 1, 2, or 3.\n")

            if relationship == 1:
                for salutation in address_acquaintence:
                    salutation = address_acquaintence[0]                
                for valediction in address_acquaintence:
                    valediction = address_acquaintence[1]

            elif relationship == 2:    
                for salutation in address_friend:
                    salutation = address_friend[0]        
                for valediction in address_friend:
                    valediction = address_friend[1]

            elif relationship == 3:
                for salutation in address_beloved:
                    salutation = address_beloved[0]      
                for valediction in address_beloved:
                    valediction = address_beloved[1]

        if relationship == 1:
            for salutation in address_acquaintence:
                salutation = address_acquaintence[0]                
            for valediction in address_acquaintence:
                valediction = address_acquaintence[1]

        elif relationship == 2:    
            for salutation in address_friend:
                salutation = address_friend[0]        
            for valediction in address_friend:
                valediction = address_friend[1]

        elif relationship == 3:
            for salutation in address_beloved:
                salutation = address_beloved[0]      
            for valediction in address_beloved:
                valediction = address_beloved[1]



        print("\nPlease inquire about %s's well being." % recipient)
        inquiry = input("You can ask about the weather, or what %s has been doing to pass the time in the interim between your last exchange:\n" % recipient)

        body = input("\nPlease write a few sentences to inform %s of the recent happenings in your life:\n" % recipient)

        final_sentiment = input("\nPlease close the letter by expressing the importance of your friendship and your desire to spend time with %s in the future:\n" % recipient ) 

        sender = input("\nWhat is your name?\n")

        postscript = input("\nPlease write a short postscript to %s:\n" % recipient) 


        # Concatenate greeting and recipient
        part_1 = salutation + " " + recipient + "," + "\n"

        # Concatenate inquiry and body
        part_2 = inquiry + " " + body + "\n"

        # Concatenate part_1, part_2, final_sentiment, closing, sender, & postscript in reverse order for a non-tradional letter format
        non_trdtnl_lttr = "P.S. " + postscript + "\n" + sender + "\n" + valediction + "\n" + final_sentiment + "\n" + part_2 + part_1

        # Using the non-traditional letter format, reverse the order of the entire letter using an extended slice to create a Looking Glass Letter & store in dictionary
        lkng_glss_lttr = non_trdtnl_lttr[::-1]
        new_lgl['lkng_glss_lttr'] = lkng_glss_lttr


        # Notify sender that their letter contents have been added to the Bot
        print(store_lkng_glss_lttr)
        print("\nYour letter to %s has been composed by the Looking Glass Letter Bot:\n" % recipient + lkng_glss_lttr)
        print("\nYour Looking Glass Letter to %s will be emailed immediately." % recipient)


        # Ask user to add another client 
        print("\nWould you like to compose another letter? Y/N")
        sender_response = input().lower().strip() 


        if sender_response == 'y' or sender_response == 'yes': 
            continue 

        else:
            print("\nWe hope you enjoyed using the Looking Glass Letter Bot.\nWe look forward to serving your Looking Glass Letter composition needs in the future.")
            break

输出应类似于：

,boB raeD

!doog m'I ?uoy era woH

!!uoy ssim I

,yllaidroC

G

.em llaC .S.P

但是，如果用户键入的数字不是1、2或3，并且必须再次提示，则亲爱的和亲切的用户不会填充。

Answer 1

在循环中，您不会将input的返回值转换为整数。

while内的if语句与用户输入一起循环

1 个答案: