Question

我需要写一条产生客户报告的报表，该报表显示所有客户，帐户和交易。包括没有交易的帐户。使用JOIN ... ON解决。并且需要-如果transaction_type是借方，请登录我的transaction_amount输出。

我尝试过使用格式，如果不是，那么... etc

这是我到目前为止所拥有的。无法弄清楚-请为我的输出签名。

select c.first_name "First", c.surname "Last",c.date_entered "Acct Date",
       t.account_type "Type", t.transaction_number "Trans #", 
       t.transaction_date "Trs Date", t.transaction_amount "Amount"
  from wgb_customer c
  join wgb_transaction t on (c.customer_number=t.customer_number) 
 order by 1,2,3,4;

Answer 1

首先，您还需要加入帐户表，并在交易表上使用LEFT OUTER JOIN，因为它也应该为没有交易的帐户创建输出。
此外，在事务类型上使用CASE语句以添加减号。
像这样的东西（尽管我没有尝试；它甚至可能无法编译）：

SELECT          cust.first_name         AS first_name,
                cust.surname            AS last_name,
                acct.account_type       AS acct_type,
                acct.date_created       AS acct_date,
                trns.transaction_number AS trans_nr,
                trns.transaction_date   AS trans_date,
                CASE
                  WHEN trns.transaction_type IS NULL THEN NULL
                  WHEN trns.transaction_type = 'D'   THEN '-' || TO_CHAR(transaction_amount, 'L99G999D99')
                  ELSE TO_CHAR(transaction_amount, 'L99G999D99')
                END                     AS amount
FROM            wgb_customer cust
JOIN            wgb_account  acct
  ON            acct.customer_number = cust.customer_number
LEFT OUTER JOIN wgb_transaction trns
             ON trns.customer_number = acct.customer_number
            AND trns.account_type    = acct.account_type
ORDER BY        last_name,
                first_name,
                acct_type,
                acct_date,
                trans_nr;

SQL将（-）符号放在我的输出前面

1 个答案: