Question

我正在学习Java正则表达式，并且在下面的程序中期望使用list [4]项目 "Its a valid number : +11234562222"，但打印为无效。我做了-在正则表达式(\\+\\d{1,2}-?)中是可选的。谁能指出该代码中缺少什么？

当前输出

> Its a valid number : 123-456-2222
Its a valid number : +1-123-456-2222
Its a valid number : 1234562222
Its a invalid number : 12345622226
Its a invalid number : +11234562222

预期产量

> Its a valid number : 123-456-2222
Its a valid number : +1-123-456-2222
Its a valid number : 1234562222
Its a invalid number : 12345622226
Its a valid number : +11234562222

public static void vali_mobile_num(){

String mob_pat = "^(\\+\\d{1,2}-?)?+(\\d{3}-?){2}+\\d{4}$";
List list = new ArrayList();

list.add( "123-456-2222");
list.add("+1-123-456-2222");
list.add("1234562222");
list.add("12345622226");
list.add("+11234562222");

Pattern p = Pattern.compile(mob_pat);

list.forEach(x -> {
    Matcher m = p.matcher(x.toString());
    if(m.find()){
        System.out.println("Its a valid number : "+m.group());
    }
    else
        System.out.println("Its a invalid number : "+ x);   

});

}

Answer 1

您的正则表达式几乎可以用，除了您多了+我不明白为什么。只需删除它，这很好。

^(\\+\\d{1,2}-?)?+(\\d{3}-?){2}+\\d{4}$
                 ^ is not needed

尝试此Java代码，

List<String> list = Arrays.asList("123-456-2222","+1-123-456-2222","1234562222","12345622226","+11234562222");
Pattern p = Pattern.compile("^(\\+\\d{1,2}-?)?(\\d{3}-?){2}+\\d{4}$");

list.forEach(x -> {
    Matcher m = p.matcher(x);
    if(m.matches()) {
        System.out.println(x + " is Valid");
    } else {
        System.out.println(x + " is Invalid");
    }
});

打印

123-456-2222 is Valid
+1-123-456-2222 is Valid
1234562222 is Valid
12345622226 is Invalid
+11234562222 is Valid

java- regex中的手机号码可选

1 个答案: