Array
(
[0 0 0 4] => Array
(
[0] => 0 0
[1] => 0 1
[2] => 0 2
[3] => 0 3
[4] => 0 4
)
[0 1 0 5] => Array
(
[0] => 0 1
[1] => 0 2
[2] => 0 3
[3] => 0 4
[4] => 0 5
)
[0 1 4 1] => Array
(
[0] => 0 1
[1] => 1 1
[2] => 2 1
[3] => 3 1
[4] => 4 1
)
[0 2 0 5] => Array
(
[0] => 0 2
[1] => 0 3
[2] => 0 4
[3] => 0 5
)
[0 2 0 6] => Array
(
[0] => 0 2
[1] => 0 3
[2] => 0 4
[3] => 0 5
[4] => 0 6
)
[0 3 1 4] => Array
(
[0] => 0 3
[1] => 0 4
[2] => 1 3
[3] => 1 4
)
[0 3 3 3] => Array
(
[0] => 0 3
[1] => 1 3
[2] => 2 3
[3] => 3 3
)
[0 3 4 3] => Array
(
[0] => 0 3
[1] => 1 3
[2] => 2 3
[3] => 3 3
[4] => 4 3
)
[0 5 1 6] => Array
(
[0] => 0 5
[1] => 0 6
[2] => 1 5
[3] => 1 6
)
[0 5 4 5] => Array
(
[0] => 0 5
[1] => 1 5
[2] => 2 5
[3] => 3 5
[4] => 4 5
)
[0 6 3 6] => Array
(
[0] => 0 6
[1] => 1 6
[2] => 2 6
[3] => 3 6
)
[0 6 4 6] => Array
(
[0] => 0 6
[1] => 1 6
[2] => 2 6
[3] => 3 6
[4] => 4 6
)
[1 0 2 1] => Array
(
[0] => 1 0
[1] => 1 1
[2] => 2 0
[3] => 2 1
)
[1 1 4 1] => Array
(
[0] => 1 1
[1] => 2 1
[2] => 3 1
[3] => 4 1
)
[1 1 5 1] => Array
(
[0] => 1 1
[1] => 2 1
[2] => 3 1
[3] => 4 1
[4] => 5 1
)
[1 2 5 2] => Array
(
[0] => 1 2
[1] => 2 2
[2] => 3 2
[3] => 4 2
[4] => 5 2
)
[1 4 2 5] => Array
(
[0] => 1 4
[1] => 1 5
[2] => 2 4
[3] => 2 5
)
[1 5 5 5] => Array
(
[0] => 1 5
[1] => 2 5
[2] => 3 5
[3] => 4 5
[4] => 5 5
)
[2 1 2 5] => Array
(
[0] => 2 1
[1] => 2 2
[2] => 2 3
[3] => 2 4
[4] => 2 5
)
[2 2 2 5] => Array
(
[0] => 2 2
[1] => 2 3
[2] => 2 4
[3] => 2 5
)
[2 2 2 6] => Array
(
[0] => 2 2
[1] => 2 3
[2] => 2 4
[3] => 2 5
[4] => 2 6
)
[2 2 3 3] => Array
(
[0] => 2 2
[1] => 2 3
[2] => 3 2
[3] => 3 3
)
[2 2 5 2] => Array
(
[0] => 2 2
[1] => 3 2
[2] => 4 2
[3] => 5 2
)
[2 5 5 5] => Array
(
[0] => 2 5
[1] => 3 5
[2] => 4 5
[3] => 5 5
)
[3 0 3 3] => Array
(
[0] => 3 0
[1] => 3 1
[2] => 3 2
[3] => 3 3
)
[3 0 3 4] => Array
(
[0] => 3 0
[1] => 3 1
[2] => 3 2
[3] => 3 3
[4] => 3 4
)
[3 1 4 2] => Array
(
[0] => 3 1
[1] => 3 2
[2] => 4 1
[3] => 4 2
)
[3 4 4 5] => Array
(
[0] => 3 4
[1] => 3 5
[2] => 4 4
[3] => 4 5
)
[4 5 5 6] => Array
(
[0] => 4 5
[1] => 4 6
[2] => 5 5
[3] => 5 6
)
)
例如，这是我的多重数组，每个键（0 1 0 5、0 1 4 1）都有其值。如果它们的值存在于先前的键数组中，那么我想将其组合成一组删除键。
例如：键“ 0 1 4 1”的值“ 0 1”存在于上一个键“ 0 1 0 5”中，在这种情况下，我们删除（取消设置）0 1 4 1。我将如何对所有元素执行此操作。并组合数组键的大小。希望你能理解
答案 0 :(得分：0)
如果我正确理解了您要做什么，这是通过使用array_intersect()过滤集合数组的一种方法。仅当当前集合和上一个集合的交集为空时，过滤器回调才应返回true。
$result = array_filter($sets, function($set) {
static $previous = [];
$matches = array_intersect($set, $previous);
$previous = $set;
return !$matches;
});
答案的第一部分中的代码显示了如何删除每个具有与前面的单个数组相同的值的数组。如果您需要删除具有与先前数组的 any 相同的值的集合，则可以这样操作：
$result = array_filter($sets, function($set) {
static $previous = [];
foreach ($set as $value) {
if (isset($previous[$value])) $matches = true;
$previous[$value] = true;
}
return empty($matches);
});