Question

在Android上，当用户在虚拟键盘上键入按键时，我没有按键事件。当用户按下“完成”按钮并且键盘关闭时，我得到了它们。但是要实现一些交互行为，我必须在用户键入密钥时获取它们。所以我尝试注册一个事件过滤器：

bool EventFilter::eventFilter(QObject *watched, QEvent *event ) {
    //qDebug() << "eventfilter: " << event->type() ;
    if (!watched) {
        return false;
    }
    if (!event) {
        return false;
    }
    if (watched->objectName() == "myedit") {
        qDebug() << "Field textedit edited: type="<< event->type();
        if (event->type() == QEvent::InputMethod) {
            QInputMethodEvent *inputMethod = static_cast<QInputMethodEvent *>(event);
            qDebug() << "inputMethod received";
            if (!inputMethod) {
                   qDebug() << "Unable to cast correct type";
            } else {
                QString commit = inputMethod->commitString();
                qDebug() << "commit str:" << commit;
                QList<QInputMethodEvent::Attribute> list= inputMethod->attributes();
                qDebug() << "attributes:";
                for (int i=0;i<list.size();i++) {
                    QInputMethodEvent::Attribute attr=list.at(i);
                    QVariant var=attr.value;
                    qDebug() << i << ": type=" << attr.type << var.toUrl();
                }

            }
        }

    }
    return false;
}

现在，当我在虚拟键盘中键入按键时，我会收到以下事件：

D MyApp: ../MyApp/eventfilter.cpp:18 (virtual bool EventFilter::eventFilter(QObject*, QEvent*)): Field textedit edited: type= QEvent::Type(InputMethodQuery)
D MyApp: ../MyApp/eventfilter.cpp:18 (virtual bool EventFilter::eventFilter(QObject*, QEvent*)): Field textedit edited: type= QEvent::Type(InputMethod)
D MyApp: ../MyApp/eventfilter.cpp:21 (virtual bool EventFilter::eventFilter(QObject*, QEvent*)): inputMethod received
D MyApp: ../MyApp/eventfilter.cpp:26 (virtual bool EventFilter::eventFilter(QObject*, QEvent*)): commit str: ""
D MyApp: ../MyApp/eventfilter.cpp:28 (virtual bool EventFilter::eventFilter(QObject*, QEvent*)): attributes:
D MyApp: ../MyApp/eventfilter.cpp:32 (virtual bool EventFilter::eventFilter(QObject*, QEvent*)): 0 : type= 1 QUrl("")
D MyApp: ../MyApp/eventfilter.cpp:32 (virtual bool EventFilter::eventFilter(QObject*, QEvent*)): 1 : type= 0 QUrl("")
D MyApp: ../MyApp/eventfilter.cpp:18 (virtual bool EventFilter::eventFilter(QObject*, QEvent*)): Field textedit edited: type= QEvent::Type(InputMethodQuery)
D MyApp: ../MyApp/eventfilter.cpp:18 (virtual bool EventFilter::eventFilter(QObject*, QEvent*)): Field textedit edited: type= QEvent::Type(InputMethodQuery)
D MyApp: ../MyApp/eventfilter.cpp:18 (virtual bool EventFilter::eventFilter(QObject*, QEvent*)): Field textedit edited: type= QEvent::Type(InputMethodQuery)

不幸的是，这种方法没有得到我预期的结果，因为我认为虚拟键盘会发送QKeyEvent对象，并且我很容易获得键码，但是它会发送InputMethod和InputMethodQuery ：(

当用户以某种方式在虚拟键盘中键入键码时，能否获得键码？

我正在使用Qt 5.11

如何使用Android上的事件过滤功能来按下按键？

0 个答案: