Question

我想将一列数据移动到行中并将其拆分为24列。为了更好地理解，我已经将数据集的示例放在下面。这是我的数据集，基本上，我想将“ bb”列划分为24列，其余列将具有与以前相同的信息。因此，从cc列将一列拆分为24列。它将重复直到结束。这是我的数据：

aa, bb, cc, dd, ee, ff, gg, hh, ii, jj, kk, ll, mm, nn
1   1  0.1 0.3 94  60  5   1  -2.  29  25  12  28  0
.
.
1   24  0.1 0.3 94  60  5   1  -2.  29  25  12  28  0

我已经将bb列拆分为该行。我的代码在这里：

import numpy as np
import pandas as pd

dataframe = pd.read_csv('dataset.csv', sep=',')

flg = 0
'''Select the features for moving one column to 24 hours columns '''
for j in range(3, 14):
'''Taking data 0 to 23'''
   for i in range(24):
        ''' select all the features in the hour column where hour value is i '''
        index_for_ith_hour_feature = np.where(dataframe.iloc[:, 1] == i)[0]
        '''if the flag value 1 it will enter the loop for making one column to 24 hour columns'''
        if flg == 1:
            '''taking all the data where jth value will be constant and 24 hours features will be selected and stacked horizontally'''
            buffer = dataframe.iloc[index_for_ith_hour_feature, j].values.reshape(-1, 1)
            '''stack all the data with buffer'''
            all_data = np.hstack((all_data, buffer))
        else:
            '''first loop will comes here because flg=0, after that, it will go to if loop and continue'''
            all_data = dataframe.iloc[index_for_ith_hour_feature, j].values.reshape(-1, 1)
            flg = 1

'''Select date columns'''
date_data_column = dataframe.iloc[index_for_ith_hour_feature, 0:2].values

'''stacking date columns and all the features previously selected'''
all_data = np.hstack((date_data_column, all_data))
print(all_data)

但是似乎我的代码做错了。我不明白问题出在哪里。到目前为止，它没有显示任何输出。从这里找出错误或实现它的更好方法对我来说真的很有帮助。谢谢。

用熊猫将一列分成多行

0 个答案: