Question

我有一个包含40个字的文本文件，例如one two three ... forty。所有单词都是彼此之间，不包含逗号。我需要将它们打印到屏幕上或彼此相邻的另一个文件中，并用逗号隔开（例如：one, two, three, ...），并且还要每十（10）或七（7）个包裹一次话。这是我的代码，无法正常工作：

import textwrap
flag = 1
comma = ', '

with open('drop_words.txt', encoding='utf-8') as file:
    content = file.read()
    content = content.split()
    words = comma.join(content)
    if len(content)%7 == 0:
        print(words, '\n')

有人可以帮忙吗？谢谢。

Answer 1

drop_words.txt：

one
two
three
four

然后：

with open('drop_words.txt', encoding='utf-8') as file:
    content = file.readlines()
    # you may also want to remove empty lines
    content = [l.strip() for l in content if l.strip()]
    print(", ".join(content), end = '')

输出：

one, two, three, four

编辑：

，如果将单词包装在一起意味着将它们分组，则可以使用grouper，例如：

import itertools as IT

def grouper(n, iterable):
    iterable = iter(iterable)
    return iter(lambda: list(IT.islice(iterable, n)), [])

with open('list.txt', encoding='utf-8') as file:
    content = file.readlines()
    content = [l.strip() for l in content if l.strip()]
    print(", ".join(content))
    grouping = ", ".join(content)
    #creating a list out of the comma separated string
    grouping = grouping.split(",")
    # grouping the two elements
    print(list(grouper(2, list(grouping))))

输出：

one, two, three, four
[['one', ' two'], [' three', ' four']]

编辑2：

OP连续提到一包10位数字

wrap = 0
newLine = True
with open('list.txt', encoding='utf-8') as file:
    content = file.readlines()
    # you may also want to remove empty lines
    content = [l.strip() for l in content if l.strip()]
    for line in content:
        if wrap < 10:
            print("{}, " .format(line), end = '')
        else:
            if newLine:
                print("\n")
                newLine = not newLine
            print("{}, ".format(line), end='')
        wrap += 1

输出：

one, two, three, four, five, six, seven, eight, nine, ten, 

eleven, twelve, thirteen, fourteen, fifteen, sixteen, seventeen, eighteen,

Answer 2

这可能完成了打印名称的工作：

with open('drop_words.txt', encoding='utf-8') as f:
    words = [line for line.strip() in f]
    print(','.join(words))

如果您想用7个单词来包装它们，可以使用以下函数：

def grouped(iterable, n):
    return zip(*[iter(iterable)]*n)

>>> grouped(word, 7)

导入单词的txt文件并在单独的行中打印单词

2 个答案: