Question

因此，这里的params是一个哈希，我想将所有键连接起来并将其存储到新字段中，如何实现呢？我发现可以在配置文件中使用嵌入式红宝石代码，但是，我不知道如何分配concat的返回值。

grok { match => { "request" => [ "url", "%{URIPATH:url_path}%{URIPARAM:url_params}?" ]} }
  urldecode{ field => "url_path" }
  mutate { gsub =>  ["url_params","\?","" ] }
  kv {
    field_split => "&"
    source => "url_params"
    target => "params"
  }
  urldecode{ field => "params" }

  ruby {
    code => 'pattern= params.keys.join(",")'
    #Pattern should be the new field that contains the key, separated by comma
  }

预期结果应该是：

pattern =“ param1，param2，param3 ...依此类推”

Answer 1

解决方案是：

event.set('field_name', field_value)

用ruby过滤器创建一个新字段

1 个答案: