Question

我想在2019年1月10日在数据框中存储所有用于NHL $ 30K芬兰语Flash的团队。到目前为止，我只能将团队存储在首页上。而且，如果用户进入了两个不同的团队，则两次都存储了他最高排名的团队...这是我的代码：

#Packages:

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as ec
import pandas as pd
import time

# Driver
chromedriver =("C:/Users/Michel/Desktop/python/package/chromedriver_win32/chromedriver.exe")
driver = webdriver.Chrome(chromedriver)

# DF taht will be use later 
results = pd.DataFrame()




calendar=[]
calendar.append("2019-01-10")


for d in calendar:
    driver.get("https://rotogrinders.com/resultsdb/date/"+d+"/sport/4/")

    time.sleep(10)
    contest= driver.find_element_by_xpath("//*[@id='root']/div/main/main/div[2]/div[3]/div/div/div[1]/div/div/div/div/div[3]")



    contest.click()
    list_links = driver.find_elements_by_tag_name('a')
    hlink=[]
    for ii in list_links:
        hlink.append(ii.get_attribute("href"))
    sub="https://rotogrinders.com/resultsdb"
    con= "contest"
    contest_list=[]
    for text in hlink:
        if sub in text:
            if con in text:
                contest_list.append(text)

    c=contest_list[2]
    driver.get(c)


    WebDriverWait(driver, 60).until(ec.presence_of_element_located((By.XPATH, './/tbody//tr//td//span//a[text() != ""]')))


# Get tables to get the user names
    tables = pd.read_html(driver.page_source)
    users_df  = tables[0][['Rank','User']]
    users_df['User'] = users_df['User'].str.replace(' Member', '')

# Initialize results dataframe and iterate through users

    for i, row in users_df.iterrows():

        rank = row['Rank']
        user = row['User']

    # Find the user name and click on the name
        user_link = driver.find_elements(By.XPATH, "//a[text()='%s']" %(user))[0]
        user_link.click()

    # Get the lineup table after clicking on the user name
        tables = pd.read_html(driver.page_source)
        lineup = tables[1]

    # Restructure to put into resutls dataframe
        lineup.loc[9, 'Name'] = lineup.iloc[9]['Salary']
        lineup.loc[10, 'Name'] = lineup.iloc[9]['Pts']

        temp_df = pd.DataFrame(lineup['Name'].values.reshape(-1, 11), 
        columns=lineup['Pos'].iloc[:9].tolist() + ['Total_$', 'Total_Pts'] )

        temp_df.insert(loc=0, column = 'User', value = user)
        temp_df.insert(loc=0, column = 'Rank', value = rank)
        temp_df["Date"]=d
        results = results.append(temp_df)        

    results = results.reset_index(drop=True)

driver.close()

所以，我想：

1）遍历所有页面：

我确实找到了next_page按钮；与：

next_button = driver.find_elements_by_xpath("//button[@type='button']")

但是，我无法在我的for循环中添加该步骤。

2）如果用户多次参加比赛，则访问不同的user_link。我认为也许可以使用这样的用户频率通过for循环来做到这一点：

users_df.groupby("User").count()

 for i in range(users_df[user,"Number"]):

     user_link = driver.find_elements(By.XPATH, "//a[text()='%s']" %(user))[i]
     user_link.click()

但是，添加这些步骤时，我总是收到一些错误消息。或者，如果运行正常，只需跳过该部分即可逐行存储所有团队，并迅速关闭驱动程序...

Answer 1

我的建议：

对于您来说，仅使用请求或任何其他等效模块来从服务器获取数据就足够了，因为您要剪贴的服务具有api服务器，例如check the link 。该示例使用第一个端点：

希望这会使您的任务更轻松。

用硒网页抓取

1 个答案: