Question

我这里的密码是二进制字符串：

01110101 01101000 01010100 01000100 01000011 01000100 00110111 00111000 00110110 00110010 00110100 01100111 00100110 00110000 00111001 00111000 00111101 ...

还有一条消息作为二进制字符串：

01001000 01100001 01101100 01101100 01101111 01101100 01100101 01101100 01100101 01100001 01110011 01100100 01100110

我尝试了多种方法对这两个字符串进行XOR，这是我的最新尝试：

public static String encrypt(String str) {
        String pwBinary = getBinaryString(pw);
        String msgBinary = getBinaryString(str);
        StringBuilder temp = new StringBuilder();


        int count = 0;


        for(int i = 0; i < msgBinary.length(); i++) {


            if(!(i%8==count)) {

                if(msgBinary.charAt(i) == pwBinary.charAt(i)) {

                    temp.append(0);
                }else {

                    temp.append(1);
                }


            }else if(i!=0) {
                temp.append(" ");
                count++;
                i++;
            }

        }
        return temp.toString();
    }

输出总是在中间的某个地方开始混乱...

0111101 0001001 0111000 0101000 0101100 0101000 1010010 1010100 10100110010100110010001110000000110010000000

我不知道如何正确处理空白处：( 在此先感谢：-）

Answer 1

我找到了一个简单的解决方案，尽管花了我一段时间才发现我的推理错误：

public static String encrypt(String str) {
        String pwBinary = getBinaryString(pw);
        String msgBinary = getBinaryString(str);
        StringBuilder temp = new StringBuilder();

        int x = 8;

        for(int i = 0; i < msgBinary.length(); i++) {


            if(i == x) {
                temp.append(" ");
                x+=9;

            }else if(msgBinary.charAt(i) == pwBinary.charAt(i)) {

            temp.append(0);
            }else {

            temp.append(1);
            }


        }
        return temp.toString();
    }

Answer 2

您的解决方案的工作版本（注释不合理的部分）为：

DECLARE @dtNow AS DATETIME = GetDate()
DECLARE @dtPast AS DATETIME = DATEADD(day,-1,GetDate())
DECLARE @dtFuture AS DATETIME = '22991231'
    SET NOCOUNT ON;

  -- Temp Table is JUST Updating Rows reflecting 
--Historical Marker on existing row No content change to row's columnar     content data 

IF OBJECT_ID('tempdb..#TheTempTableName') IS NOT NULL DROP TABLE     #TheTempTableName


CREATE TABLE #TheTempTableName 
(
    ABunchOfColumns
    RowCreatedDate datetime NULL,
    RowEffectiveDate datetime NULL,
    RowTerminationDate datetime NULL,
    RowIsCurrent bit NULL,
    RowHash varchar(max) NULL,
)

INSERT INTO #TheTempTableName
(
            ABunchOfColumns
                ,RowCreatedDate
                ,RowEffectiveDate
                ,RowTerminationDate
                ,RowIsCurrent
                ,RowHash 
)


SELECT
                ABunchOfColumns
                ,RowCreatedDate
                ,RowEffectiveDate
                ,RowTerminationDate
                ,RowIsCurrent
                ,RowHash 
FROM
    (
        MERGE tblDim WITH (HOLDLOCK) AS target
            USING 
            (
                SELECT          
                ABunchOfColumns
                ,RowCreatedDate
                ,RowEffectiveDate
                ,RowTerminationDate
                ,RowIsCurrent
                ,RowHash 

                FROM dbo.tblStaging
            )       
        AS source
        ON target.PKID  = source.PKID       
        WHEN MATCHED
            AND target.RowIsCurrent = 1
            AND target.RowHash != source.RowHash                    
------- PROCESS ONE -- UPDATE --- HISTORICALLY MARK EXISTING ROWS
            THEN UPDATE SET                     
                    RowEffectiveDate    =   @dtPast
                    ,RowTerminationDate =   @dtPast
                    ,RowIsCurrent   =   0                   
-----  PROCESS TWO -- INSERT ---INSERT NEW ROWS
            WHEN NOT     MATCHED                                                          
            THEN INSERT    ---   THIS INSERT Goes directly into Target ( DIM     ) Table (New Rows not matched with PK = PK ) 
                (
                ABunchOfColumns
                ,RowCreatedDate
                ,RowEffectiveDate
                ,RowTerminationDate
                ,RowIsCurrent
                ,RowHash 
                )
                VALUES
                (                   
                source.ABunchOfColumns
                    ,@dtNow                 --source.RowCreatedDate,
                    ,@dtFuture              ---source.RowEffectiveDate,
                    ,@dtFuture              ---source.RowTerminationDate,
                    ,1                      ---source.RowIsCurrent,
                    ,source.RowHash
                )
-------PROCESS THREE a  -- INSERT ---OUTPUT MATCHED ROWS FROM PROCESS ONE THAT CAUSED     HISTORICAL MARK (CHANGES) "INSERT"
        OUTPUT 
        $action Action_Out,

                ABunchOfColumns
                ,RowCreatedDate
                ,RowEffectiveDate
                ,RowTerminationDate
                ,RowIsCurrent
                ,RowHash 
    )       
    AS MERGE_OUT
WHERE MERGE_OUT.Action_Out = 'UPDATE';

----------PROCESS THREE b  -- INSERT FROM Temp Tbl to final
--Now we flush the data in the temp table into dim table

INSERT INTO tblDim
    (
                ABunchOfColumns
                ,RowCreatedDate
                ,RowEffectiveDate
                ,RowTerminationDate
                ,RowIsCurrent
                ,RowHash 
    )
SELECT
         ABunchOfColumns
        ,@dtNow AS RowCreatedDate
        ,@dtFuture AS RowEffectiveDate
        ,@dtFuture AS RowTerminationDate
        ,1 AS RowIsCurrent
        ,RowHash

FROM #TheTempTableName  
END

但是达到目标的更快（cpu工作量）的方法是：

public static String encrypt(String str) {
    String pwBinary = getBinaryString(pw);
    String msgBinary = getBinaryString(str);
    StringBuilder temp = new StringBuilder();
    //no idea what count was supposed to do!!!
    for(int i = 0; i < msgBinary.length(); i++) {
        if(((i+1)%9!=0)) {//the space occurs once in every 9 times
            if(msgBinary.charAt(i) == pwBinary.charAt(i)) {
                temp.append(0);
            }else {
                temp.append(1);
            }
        }else {
            temp.append(" ");
            //why should we increment i? the for loop does it automatically!
        }
    }
    return temp.toString();
}

XOR加密包含空格的位字符串时出现问题

2 个答案: