我的数据库中有两个表。一个叫做wp_tickets
,另一个叫wp_tickets_regenerated
。
如果wp_tickets_regenerated
匹配,我试图从wp_tickets
表中更新lottery_id
表中的某些数据,所以我最终得到了一个新表,该表生成了不同的ticket_number该产品的每个订单。
到目前为止,我的代码抛出错误:
WordPress database error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM wp_tickets
WHERE lottery_id = wp_tickets.lottery_id' at line 6 for query UPDATE wp_tickets_regenerated
有人可以帮忙吗?
wp_tickets表
+---------+-----------+-----------+---------------+----------+------------+
| user_id | full_name | answer_id | ticket_number | order_id | lottery_id |
+---------+-----------+-----------+---------------+----------+------------+
| 0 | test | 1 | 3 | 791 | 790 |
+---------+-----------+-----------+---------------+----------+------------+
| 0 | test | 1 | 5 | 791 | 790 |
+---------+-----------+-----------+---------------+----------+------------+
| 0 | test | 1 | 10 | 791 | 790 |
+---------+-----------+-----------+---------------+----------+------------+
wp_tickets_regeneration
+---------+-----------+-----------+---------------+----------+------------+
| user_id | full_name | answer_id | ticket_number | order_id | lottery_id |
+---------+-----------+-----------+---------------+----------+------------+
| | | | 1 | | 790 |
+---------+-----------+-----------+---------------+----------+------------+
| | | | 2 | | 790 |
+---------+-----------+-----------+---------------+----------+------------+
| | | | 3 | | 790 |
+---------+-----------+-----------+---------------+----------+------------+
我到目前为止有:
$wpdb->query(
'UPDATE wp_tickets_regenerated
SET user_id = wp_tickets.user_id,
full_name = wp_tickets.full_name,
answer_id = wp_tickets.answer_id,
order_id = wp_tickets.order_id
FROM wp_tickets
WHERE lottery_id = wp_tickets.lottery_id'
);
答案 0 :(得分:1)
您需要一个内部联接表 SELECT CodeID codes , COUNT(DISTINCT ClientID) clients
FROM Entry
GROUP BY codes ORDER BY Codes
进行更新
尝试
wp_tickets
希望这对您有帮助
答案 1 :(得分:0)
可能需要内部联接进行更新
UPDATE wp_tickets_regenerated a
INNER JOIN wp_tickets b a.lottery_id = b.lottery_id
SET a.user_id = b.user_id,
a.full_name = b.full_name,
a.answer_id = b.answer_id,
a.order_id = b.order_id
(不使用更新中的...)