Question

我有一些JSON字符串，其中一些与以下字符串匹配：

{"name":"Example diagnosis 1","code":"111609001","table":"SNOMEDCT","addedby":"EDnurse","dateadded":1548080768169,"qualifier":[{"name":"Qualifier","value":"Confirmed Diagnosis","code":"410605003","prefix":"[C] "},{"name":"Left/Right","value":"Bilateral","code":"51440002","suffix":" - Bilateral"}],"prefix":"[C] ","suffix":" - Bilateral"},{"name":"Example diagnosis 2","code":"371162008","table":"SNOMEDCT","addedby":"EDnurse","dateadded":1548080778007,"qualifier":[{"name":"Qualifier","value":"Confirmed Diagnosis","code":"410605003","prefix":"[C] "},{"name":"Left/Right","value":"Bilateral","code":"51440002","suffix":" - Bilateral"}],"prefix":"[C] ","suffix":" - Bilateral"}

我建立了以下case语句，该语句部分起作用，并返回以下带有回车符和换行符的字符串，替换逗号：

{"name":"Example diagnosis 1","code":"111609001","table":"SNOMEDCT","addedby":"EDnurse","dateadded":1548080768169,"qualifier":[{"name":"Qualifier","value":"Confirmed Diagnosis","code":"410605003","prefix":"[C] "},{"name":"Left/Right","value":"Bilateral","code":"51440002","suffix":" - Bilateral"}],"prefix":"[C] ","suffix":" - Bilateral"}
{"name":"Example diagnosis 2","code":"371162008","table":"SNOMEDCT","addedby":"EDnurse","dateadded":1548080778007,"qualifier":[{"name":"Qualifier","value":"Confirmed Diagnosis","code":"410605003","prefix":"[C] "},{"name":"Left/Right","value":"Bilateral","code":"51440002","suffix":" - Bilateral"}],"prefix":"[C] ","suffix":" - Bilateral"}

这是我的CASE声明：

select 
     CASE 
          WHEN notevalue LIKE '%"suffix":" - Bilateral"},%'
          THEN REPLACE(substring(LEFT(cast(notevalue as varchar(8000)),DATALENGTH(cast(notevalue as varchar(8000)))-1), 2, 8000),'"suffix":" - Bilateral"},','"suffix":" - Bilateral"}'+CHAR(13)+CHAR(10))
          ELSE substring(LEFT(cast(notevalue as varchar(8000)),DATALENGTH(cast(notevalue as varchar(8000)))-1), 2, 8000)
        END as test
from clinicalnotesdata
where notekey = 'ed diagnosis'
and visitid = '6948'

但是，我还需要它在我的CASE语句中添加其他2个实例，以捕获其他字符串（所有字符串都单独工作）。一旦我结合了该案例的3个场景，它就明显与第一个场景匹配并结束。但是有时字符串会匹配所有3种情况。

WHEN notevalue LIKE '%"prefix":"[[]C] "},%'
THEN REPLACE(substring(LEFT(cast(notevalue as varchar(8000)),DATALENGTH(cast(notevalue as varchar(8000)))-1), 2, 8000),'"prefix":"[C] "}],"prefix":"[C] "},','"prefix":"[C] "}],"prefix":"[C] "}'+CHAR(13)+CHAR(10))

WHEN notevalue LIKE '"%prefix":"[[]C] ","suffix":" - Right"},%'
THEN REPLACE(substring(LEFT(cast(notevalue as varchar(8000)),DATALENGTH(cast(notevalue as varchar(8000)))-1), 2, 8000),'"prefix":"[C] ","suffix":" - Right"},','"prefix":"[C] ","suffix":" - Right"}'+CHAR(13)+CHAR(10))

本质上，我需要用CHAR（13）+ CHAR（10）替换特定的逗号，以满足以上3条条件中的全部或部分条件。

有什么想法吗？谢谢。

Answer 1

解决此问题的最佳方法是使用我称之为与APPLY进行别名的技巧；这是保持代码DRYer的一种方式（DRY =不要重复自己）。您可以像这样简化代码：

SELECT 
  CASE
    WHEN CHARINDEX(a.stxt+',',t.notevalue) > 0  --WHEN t.notevalue LIKE '%"suffix":" - Bilateral"},%'
    THEN REPLACE(a2.string,a.stxt+',',a.stxt+CHAR(13)+CHAR(10))
    ELSE a2.string
  END as test
FROM        @clinicalnotesdata AS t
CROSS APPLY (VALUES(CAST(t.notevalue AS VARCHAR(8000)),
                    DATALENGTH(t.notevalue)-1, '"suffix":" - Bilateral"}')) AS a(nval,dl,stxt)
CROSS APPLY (VALUES(SUBSTRING(LEFT(a.nval,DATALENGTH(a.nval)-1), 2, 8000))) AS a2(string)
WHERE       t.notekey = 'ed diagnosis'
AND         t.visitid = '6948';

此代码将执行完全相同的操作，并且如您所见，它更易于理解和重用。例如，CAST(t.notevalue AS VARCHAR(8000)的所有四个实例已被a.nval替换，DATALENGTH(t.notevalue)-1的两个实例已被a.dl替换。 substring(LEFT(cast(notevalue as varchar(8000)),DATALENGTH(cast(notevalue as varchar(8000)))-1), 2, 8000)的两个实例现已删除。

如您所见，我正在使用VALUES构造函数和APPLY创建内联函数，这些内联函数只是对重复的代码块进行别名。相信我，像这样开始编写代码，做起来会容易得多，否则会导致您费劲。

SQL-用回车符和JSON字符串中的换行符替换字符

1 个答案: