Question

我正在尝试从以下教程中编写代码： https://www.youtube.com/watch?v=9mAmZIRfJBs&t=197s 在我看来，我完全是用相同的方式编写的，但是仍然会出现错误。有人可以向我解释为什么Spyder（Python 3.7）会这样做。这是我的代码：

我尝试使用另一个输入函数，所以用raw_input代替了输入。我还尝试过更改工作目录并保存文档

这是我的代码：

# -*- coding: utf-8 -*-
"""
Created on Tue Jan 29 14:47:27 2019

@author: johan
"""

import random

restaurantsList = ['boloco', 'clover', 'sweetgreens']

def pickRestaurant():
    print(restaurantsList[random.randint(0,2)])

def addRestaurant(name):
    restaurantsList.append(name)

def removeRestaurant(name):
    restaurantsList.remove(name)

def listRestaurant():
    for restaurant in restaurantsList:
        print(restaurant)

while True: 
    print('''

   [1] - List restaurant
   [2] - Add restaurant
   [3] - Remove restaurant
   [4] - Pick restaurant
   [5] - Exit

''')
   selection = raw_input(prompt='Please select an option: ')

   if selection == '1':
       print('')
       listRestaurant()
   elif selection == '2':
       inName = raw_input(prompt='Type name of the restaurant that you want to add: ')
       addRestaurant(inName)
   elif selection == '3':
       inName = raw_input(prompt='Type name of the restaurant that you want to remove: ')
       removeRestaurant(inName)
   elif selection == '4':
       pickRestaurant()
   elif selection == '5':
       break

这是错误

    runfile('C:/Users/johan/Desktop/Unie jaar 2/untitled2.py', wdir='C:/Users/johan/Desktop/Unie jaar 2')
Traceback (most recent call last):

  File "C:\Users\johan\Anaconda3\lib\site-packages\IPython\core\interactiveshell.py", line 3267, in run_code
exec(code_obj, self.user_global_ns, self.user_ns)

  File "<ipython-input-93-2d7193d6cafb>", line 1, in <module>
runfile('C:/Users/johan/Desktop/Unie jaar 2/untitled2.py', wdir='C:/Users/johan/Desktop/Unie jaar 2')

  File "C:\Users\johan\Anaconda3\lib\site-packages\spyder_kernels\customize\spydercustomize.py", line 704, in runfile
execfile(filename, namespace)

  File "C:\Users\johan\Anaconda3\lib\site-packages\spyder_kernels\customize\spydercustomize.py", line 108, in execfile
exec(compile(f.read(), filename, 'exec'), namespace)

  File "C:/Users/johan/Desktop/Unie jaar 2/untitled2.py", line 35
selection = raw_input(prompt='Please select an option: ')
                                                         ^
IndentationError: unindent does not match any outer indentation level

应该给餐厅清单的代码是放置1个餐厅。如果放置2个餐厅，则可以将餐厅添加到列表中。想要添加3个餐厅，然后将其删除。 4从列表中选择一个随机餐厅。 5什么也不做。

Answer 1

因此必须在Python中正确缩进；

# -*- coding: utf-8 -*-
"""
Created on Tue Jan 29 14:47:27 2019

@author: johan
"""

import random

restaurantsList = ['boloco', 'clover', 'sweetgreens']

def pickRestaurant():
  print(restaurantsList[random.randint(0,2)])

def addRestaurant(name):
  restaurantsList.append(name)

def removeRestaurant(name):
  restaurantsList.remove(name)

def listRestaurant():
  for restaurant in restaurantsList:
    print(restaurant)

while True: 
  print('''
  [1] - List restaurant
  [2] - Add restaurant
  [3] - Remove restaurant
  [4] - Pick restaurant
  [5] - Exit
  ''')
  selection = input('Please select an option: ')
  if selection == '1':
    print('')
    listRestaurant()
  elif selection == '2':
    inName = input('Type name of the restaurant that you want to add: ')
    addRestaurant(inName)
  elif selection == '3':
    inName = input('Type name of the restaurant that you want to remove: ')
    removeRestaurant(inName)
  elif selection == '4':
    pickRestaurant()
  elif selection == '5':
    break

Python是缩进敏感的，创建函数或任何语句时，您需要缩进该函数内的任何代码，否则您将得到上面的错误。

附加说明：您使用的是print()（它是python2）和raw_input（它是python3），所以我假设使用Python3，并将raw_input()更改为input()。 / p>

Answer 2

print循环中的while语句之前有4个空格，但是该循环中的所有其他行仅从selection = raw_input...开始有3个空格缩进

您应该在selection = raw_input...及以下的每一行的开头添加一个空格。

我不理解的错误

2 个答案: