Question

我有一个查询，以前在MS SQL中使用过，想在Oracle中使用。但是，它将返回缺少的表达式。

我需要来自同一表的数据，但具有无法在同一查询中组合的不同参数。

TABLE TTT

DATE        LIC      ITEM   QTY  SU
20-01-2019  L991234  P0042   20  S002201
20-01-2019  L991234  P0042   40  S002202
20-01-2019  L991234  P0042   60  S002203
20-01-2019  L991234  P0042   80  S002204
20-01-2019  L991234  P0042  100  S002205
21-01-2019  L991245  P0069   30  S003101
21-01-2019  L991245  P0069   60  S003102
21-01-2019  L991245  P0069   90  S003103
21-01-2019  L991245  P0069  120  S003104
22-01-2019  L991256  P0042   20  S004301
22-01-2019  L991256  P0042   40  S004302
22-01-2019  L991256  P0042   60  S004303
22-01-2019  L991256  P0042   80  S004304
23-01-2019  L991264  P0069   30  S007501
23-01-2019  L991264  P0069   60  S007502
23-01-2019  L991271  P0042   20  S008801
23-01-2019  L991271  P0042   40  S008802

查询：

SELECT TA.ITEM, TA.CNT, TB.CNT
FROM (
SELECT  1 typ, DISTINCT TTT.ITEM, TTT.NO, COUNT(DISTINCT TTT.LIC)
    FROM TTT
    WHERE TTT.TYPE = '6' AND TTT.ITEM = 'H01234'
    GROUP BY   TTT.ITEM,TTT.LIC
    ORDER BY TTT.ITEM, TTT.NO
) TA
INNER JOIN
  (
SELECT  2 typ, DISTINCT TTT.ITEM, COUNT(DISTINCT TTT.SU)
   FROM TTT
        WHERE TTT.TYPE = '6' AND TTT.ITEM = = 'H01234'
        GROUP BY   TTT.ITEM, TTT.SU
        ORDER BY TTT.ITEM
) TB ON TA.ITEM = TB.ITEM
ORDER BY TA.ITEM

预期结果

TA.ITEM  TA.CNT  TB.CNT
P0042         3      11
P0069         2       6

Answer 1

您可以更简单地完成操作，而无需联接和联合：

^{dbfiddle demo}

select item, count(distinct lic) cnt1, count(distinct su) cnt2
  from ttt 
  group by item

结果：

ITEM        CNT1       CNT2
----- ---------- ----------
P0042          3         11
P0069          2          6

Answer 2

DISTINCT应该跟随SELECT；您有两个连续的=

在修复该问题之后，查询看起来不错（但我不知道它是否返回所需的数据）：

  SELECT TA.ITEM, TA.CNT, TB.CNT
    FROM (  SELECT DISTINCT 1 typ,                        --> here
                            TTT.ITEM,
                            TTT.NO,
                            COUNT (DISTINCT TTT.LIC)
              FROM TTT
             WHERE     TTT.TYPE = '6'
                   AND TTT.ITEM = 'H01234'
          GROUP BY TTT.ITEM, TTT.LIC
          ORDER BY TTT.ITEM, TTT.NO) TA
         INNER JOIN (  SELECT DISTINCT 2 typ,            --> here
                              TTT.ITEM, COUNT (DISTINCT TTT.SU)
                         FROM TTT
                        WHERE     TTT.TYPE = '6'
                              AND TTT.ITEM = 'H01234'    --> here
                     GROUP BY TTT.ITEM, TTT.SU
                     ORDER BY TTT.ITEM) TB
            ON TA.FROM_ITEM = TB.FROM_ITEM
ORDER BY TA.ITEM

Answer 3

可能是join子句为ON TA.ITEM = TB.ITEM而不是ON TA.FROM_ITEM = TB.FROM_ITEM

    SELECT TA.ITEM, TA.CNT, TB.CNT
    FROM (
        SELECT  1 typ, DISTINCT TTT.ITEM, TTT.NO, COUNT(DISTINCT TTT.LIC)
            FROM TTT 
            WHERE TTT.TYPE = '6' AND TTT.ITEM = 'H01234' 
            GROUP BY   TTT.ITEM,TTT.LIC
            ORDER BY TTT.ITEM, TTT.NO
    ) TA
    INNER JOIN  ( 
        SELECT  2 typ, DISTINCT TTT.ITEM, COUNT(DISTINCT TTT.SU)
           FROM TTT 
                WHERE TTT.TYPE = '6' AND TTT.ITEM = = 'H01234'   
                GROUP BY   TTT.ITEM, TTT.SU
                ORDER BY TTT.ITEM
    ) TB ON TA.ITEM = TB.ITEM
    ORDER BY TA.ITEM

有没有一种方法可以在Oracle中使用SQL Join？

3 个答案: