Question

我有示例数据

Name    Product Prd_cnt Prd_dt
BSA     CYCLE   20      29-01-2019
BSA     CYCLE   20      28-01-2019
BSA     CYCLE   20      27-01-2019
BSA     CYCLE   20      26-01-2019
BSA     CYCLE   40      25-01-2019
BSA     CYCLE   35      24-01-2019
BSA     CYCLE   35      23-01-2019
BSA     CYCLE   35      22-01-2019

即使日期不同，我也需要选择最近4天具有相同计数的记录。从当前日期到过去4天。如果其中一个记录与最近4天不同。不需要那些记录。

输出：

Name  Product   Prd_cnt   Prd_dt
BSA   CYCLE     20        29-01-2019
BSA   CYCLE     20        28-01-2019
BSA   CYCLE     20        27-01-2019
BSA   CYCLE     20        26-01-2019

我尝试使用ROW_NUMBER并拥有COUNT()。

Answer 1

只需使用BETWEEN和DATEADD()来查找最近4天的结果：

SELECT * FROM YourTable
WHERE PRD_DT BETWEEN CAST(DATEADD(DAY,-3,GETDATE()) AS DATE) 
                AND  CAST(GETDATE() AS DATE)

Answer 2

我只会使用exists。

首先，创建并填充示例表（请在您将来的问题中为我们保存此步骤）：

CREATE TABLE T(
  Name   VARCHAR(50),
  Product VARCHAR(50),
  Prd_cnt INT,
  Prd_dt  DATE
);

INSERT INTO T (Name, Product, Prd_cnt, Prd_dt) VALUES 
('BSA','CYCLE',20,'2019-01-29'),
('BSA','CYCLE',20,'2019-01-28'),
('BSA','CYCLE',20,'2019-01-27'),
('BSA','CYCLE',20,'2019-01-26'),
('BSA','CYCLE',40,'2019-01-25'),
('BSA','CYCLE',35,'2019-01-24'),
('BSA','CYCLE',35,'2019-01-23'),
('BSA','CYCLE',35,'2019-01-22'),
('BSA','CYCLE',40,'2019-01-21');

然后是一个简单的公用表表达式和一个存在的子查询：

WITH CTE AS
(
    SELECT Name,Product,Prd_cnt,Prd_dt
    FROM T As t0
    WHERE Prd_dt <= GETDATE()
    AND Prd_dt >= CAST(DATEADD(DAY, -3, GETDATE()) As Date)
)
SELECT Name,Product,Prd_cnt,Prd_dt
FROM CTE As t0
WHERE EXISTS
(
    SELECT 1
    FROM CTE As t1
    WHERE t0.Prd_dt <> t1.Prd_dt
    AND t0.Prd_cnt = t1.Prd_cnt
)

公用表表达式会选择最近四天的所有记录，而exist仅过滤具有重复Prd_cnt值的记录。
请注意，如果您想让重复项也考虑其他列，您要做的就是将它们添加到exist子查询where子句中。

感谢D-Shih为DDL + DML样本数据创建小提琴。

Answer 3

您可以尝试

SELECT distinct Orders.*
FROM (
    SELECT Name, Product, Prd_cnt, ROW_NUMBER ()   
    OVER (PARTITION BY Name, Product, Prd_cnt order by Prd_dt)  as RN 
    FROM Orders 
)t 
inner join Orders on t.Name = Orders.Name and t.Prd_cnt = Orders.Prd_cnt
and t.Product = Orders.Product where RN >= 4 AND Orders.Prd_dt < GetDate()

Answer 4

请尝试以下查询：

select * from myTable t1
where Prd_dt > cast(dateadd(day, -4, getdate()) as date)
and exists(select 1 from myTable
           where Prd_dt > cast(dateadd(day, -4, getdate()) as date)
           and product = t1.product
           group by product
           having count(*) > 1)

如果特定的Product有两个以上的记录，则子查询将返回行，这又将产生所有行，并且在最近四天内重复了Product的值。

Answer 5

您可以尝试

SELECT * FROM T WHERE Prd_cnt=(SELECT Prd_cnt FROM T HAVING COUNT(Prd_cnt)>1) and 
DATEDIFF(CURRENT_TIMESTAMP,(
SELECT Prd_dt FROM T WHERE DATEDIFF(CURRENT_TIMESTAMP,Prd_dt)<4 ORDER BY Prd_dt LIMIT 1));

需要根据当前日期选择重复项

5 个答案: