Question

初学者的问题，我有一个多项目sbt文件，如果我在文件的开头放置常规设置，会有区别吗？例如：

<Album>

或者如果我将其设置为常用设置

organization := "com.example"
  version := "0.0.1-SNAPSHOT"
  scalaVersion := "2.11.12"
resolvers ++= Seq(
    "Apache Development Snapshot Repository" at "https://repository.apache.org/content/repositories/snapshots/",
    "Typesafe repository" at "http://repo.typesafe.com/typesafe/releases/",

    Resolver.mavenLocal
  )
assemblyMergeStrategy in assembly := {
    case PathList("META-INF", xs @ _*) => MergeStrategy.discard
    case x => MergeStrategy.first
  }
lazy val commonSettings  = Seq(  libraryDependencies ++= commonDependencies ++ testingDependencies)
lazy val sharedProject = (project in file(...))
.settings(commonSettings: _*)
val projectA = .....dependsOn(sharedPorject)
val projectB = .....dependsOn(sharedPorject)

有什么区别？

Answer 1

定义的任何未附加到特定项目的设置的设置，即.settings()，都将附加到根项目。

这样的代码

organization := "foo"

与

相同

lazy val root = (project in file(".")).settings(organization := "foo")

现在，如果您定义了一个新的子项目，例如common，并向其中添加了organization

lazy val common = (project in file("common")).settings(organization := "bar")

并且只有它的值organization设置为bar。

在根项目也定义了自己的organization的情况下，这将保留在示例中。

lazy val root = (project in file(".")).settings(organization := "foo")

lazy val common = (project in file("common")).settings(organization := "bar")

使用命令sbt "show organization"和sbt "show common/organization"可以轻松测试。它将分别打印foo和bar。

最后，如果您希望为所有子项目定义相同的值，请在根项目中为范围ThisBuild添加设置，如下例所示：

organization in ThisBuild := "foo"

lazy val common = (project in file("common")).settings(???)

或将设置存储在Seq中，并将其应用于所有子项目和root。这将与作用域ThisBuild中的作用类似，但更加明确：

val commonSettings = Seq(organization := "foo")

lazy val root = (project in file(".")).settings(commonSettings)
lazy val common = (project in file("common")).settings(commonSettings)

SBT在文件或多项目中的commonSettings中放置设置有什么区别

1 个答案: