Question

Hello All

在我的android项目中，我想显示一个特定的单词，在字符串中说TRIAL这是我的Trial.This试验只是为了好玩。如何在android中实现这一点。

我尝试使用下面的代码，它只会格式化15到30之间的字符串。

TextView TV = (TextView)findViewById(R.id.mytextview01); 
Spannable WordtoSpan = new   SpannableString("I know just how to whisper, And I know    just how to cry,I know just where to find the answers");  
 WordtoSpan.setSpan(new ForegroundColorSpan(Color.BLUE), 15, 30,Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
 TV.setText(WordtoSpan);

请告诉我是否可以在Android中执行此操作。

请转发您宝贵的建议。

提前致谢：）

Answer 1

尝试在String类中使用indexOf（String str）方法。这将为您提供您在Spannable中搜索的单词的第一次出现（这是一个扩展的字符串）。然后，您可以相应地应用颜色范围。

Answer 2

在Scythe的答案上稍微扩展一下，用以下内容替换它们：

public class Junk extends Activity {

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        TextView tv = (TextView) findViewById(R.id.textView1);
        String tvText = "This is for my Trial.This Trial is just for fun. Just a Trial";
        tvText+="A Trial. Only a Trial. It's a Trial"; 
        String lookFor = "Trial";
        tv.setText(formatString(tvText, lookFor));
    }

    private Spannable formatString(String targetStr, String lookFor) {

        Spannable spanString = null;
        spanString = new SpannableString(targetStr);
        int fromIndex, startSpan, endSpan;

        fromIndex = 0;
        while (fromIndex < (targetStr.length() - 1)) {
            startSpan = targetStr.indexOf(lookFor, fromIndex);
            if (startSpan == -1)
                break;
            endSpan = startSpan + lookFor.length();
            spanString.setSpan(new ForegroundColorSpan(Color.BLUE), startSpan,
                    endSpan, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
            fromIndex = endSpan; 
        }
        return spanString;
    }
}

跨越android中的特定单词

2 个答案: