Question

我有一行类似

date |v3| 0.00| 0.00| 0.00| 0| 0| 7324.00| 0.00| 12278 12276|Tue Jan 29 09:36:47

我要迭代此行并形成类似这样的输出

["date" ,"v3" ,"0.00" ,"0.00" ,"0.00" ,"0" ,"0" ,"7324.00" ,"0.00" ,"12278 12276","Tue Jan 29 09:36:47"]

我想使用shell脚本实现此目标，我该如何实现？

Answer 1

第一种解决方案： 。能否请您尝试以下操作。

awk -v s1="\",\"" -v s2="\"" '{gsub(/\|/,s1);$0="[" s2 $0 s2 "]"} 1' Input_file

输出如下。

["date ","v3"," 0.00"," 0.00"," 0.00"," 0"," 0"," 7324.00"," 0.00"," 12278 12276","Tue Jan 29 09:36:47"]

第二种解决方法： 或者，要处理不均匀的空间，请尝试以下方法。

awk -v s1="\",\"" -v s2="\"" -v s3="\" ,\"" '{gsub(/ \||\| /,s3);gsub(/\|/,s1);$0="[" s2 $0 s2 "]"} 1' Input_file

OR（上面的一个非衬里形式）：

awk -v s1="\",\"" -v s2="\"" -v s3="\" ,\"" '
{
  gsub(/ \||\| /,s3)
  gsub(/\|/,s1)
  $0="[" s2 $0 s2 "]"
}
1
'  Input_file

输出如下。

["date" ,"v3" ,"0.00" ,"0.00" ,"0.00" ,"0" ,"0" ,"7324.00" ,"0.00" ,"12278 12276","Tue Jan 29 09:36:47"]

Answer 2

您似乎将信息保存在列表结构[..]中，这与Python中的构造非常同义词，该构造不是容易在bash中实现（具有数组）或Awk。

您只需执行以下操作

import json
str='date |v3| 0.00| 0.00| 0.00| 0| 0| 7324.00| 0.00| 12278 12276|Tue Jan 29 09:36:47'
split_str = str.split("|")
wo_spaces = [ str.strip() for str in split_str ]
print( json.dumps( wo_spaces ) )
["date", "v3", "0.00", "0.00", "0.00", "0", "0", "7324.00", "0.00", "12278 12276", "Tue Jan 29 09:36:47"]

Answer 3

一种简单的sed方式：

sed 's/\s*|\s*/","/g;s/^/["/;s/$/"]/'

输出：

["date","v3","0.00","0.00","0.00","0","0","7324.00","0.00","12278 12276","Tue Jan 29 09:36:47"]

Answer 4

使用Perl

$ export a='date |v3| 0.00| 0.00| 0.00| 0| 0| 7324.00| 0.00| 12278 12276|Tue Jan 29 09:36:47'
$ echo $a | perl -F"\s*\|\s*" -lane ' $_="\x22".$_."\x22" for(@F); print "[",join(",",@F),"]" '
["date","v3","0.00","0.00","0.00","0","0","7324.00","0.00","12278 12276","Tue Jan 29 09:36:47"]
$

使用Python中的分隔字符串创建双引号条目列表

4 个答案: