Question

S0，基本上，我写了一个更长的程序，用另一种语言测试我的时态。它根据掷出的骰子随机测试我。但是，由于某些原因，我引用的代码片段无效。问题是，如果我输入“ present”或“ future”，则会跳至else部分。 “两者”均出于某种原因起作用。我究竟做错了什么？真的很烦我，因为我看不到任何问题。

tenses_tested = input("Would you like to be tested on the present, future simple, or both?")

if "present" in tenses_tested:
    roll_range = 6
    roll_addition = 0
if "future" in tenses_tested:
    roll_range = 6
    roll_addition = 6
if "both" in tenses_tested:
    roll_range = 13
    roll_addition = 0
else:
    print("Something went wrong because this keeps coming up...")
    roll_range = 13
    roll_addition = 0

Answer 1

if "present" in tenses_tested:
    roll_range = 6
    roll_addition = 0
elif "future" in tenses_tested:
    roll_range = 6
    roll_addition = 6
elif "both" in tenses_tested:
    roll_range = 13
    roll_addition = 0
else:
    ...

在else仅附加到if "both" ...

之前

通过使用elif，我们将它们全部附加到else上，如果有任何工作，它将不会放在else上

Answer 2

不，不是这样。根据您输入的是“现在”还是“未来”，它成功进入if块。但是到了最后一个条件。该条件与前两个条件无关，而else仅适用于该条件；因此，由于第三个if为假，则else将会被触发，并将覆盖原始值。

解决方案是使用elif使它们全部成为同一块的一部分。

if "present" in tenses_tested:
    roll_range = 6
    roll_addition = 0
elif "future" in tenses_tested:
    roll_range = 6
    roll_addition = 6
elif "both" in tenses_tested:
    roll_range = 13
    roll_addition = 0
else:
    print("Something went wrong because this keeps coming up...")
    roll_range = 13
    roll_addition = 0

Answer 3

问题是您使用的是if而不是elif语句，因此您的代码正在测试这三个条件。例如，如果在"present" in tenses_tested:块中添加了一条打印语句，您将意识到它进入了该块。但是它也进入了未来，并且进入了两个障碍，并且因为您键入的内容是！=“ both”，所以进入了其他地方。将来也会发生同样的情况，但两者却不会，因为这是最后的声明。这应该起作用：

tenses_tested = input("Would you like to be tested on the present, future simple, or both?")

if "present" in tenses_tested:
    roll_range = 6
    roll_addition = 0
elif "future" in tenses_tested:
    roll_range = 6
    roll_addition = 6
elif "both" in tenses_tested:
    roll_range = 13
    roll_addition = 0
else:
    print("Something went wrong because this keeps coming up...")
    roll_range = 13
    roll_addition = 0

如何检查字符串是否包含单词？

3 个答案: