当我输出'mat'时，它按预期工作，其中mat提供矩阵的整个列表，mat [1]，mat [2]和mat [3]提供第一个第二和第三个元素，即4x4矩阵，所有条目分别等于1、2和3。
但是，当我尝试添加新元素或更改现有元素时，出现错误，并且没有在列表中添加4x4矩阵，而是添加了常规数字。
如何将新矩阵添加到列表中？我也愿意使用list（）的替代方法。我对R相对较新，我一直使用x = c（），但这似乎也不适用于矩阵。预先感谢。
输入：
mat = list( matrix (c(1), nrow = 4, ncol = 4, byrow = TRUE),
matrix (c(2), nrow = 4, ncol = 4, byrow = TRUE),
matrix (c(3), nrow = 4, ncol = 4, byrow = TRUE) )
mat
mat[2]
mat[1] = matrix(c(0), nrow = 4, ncol = 4, byrow = TRUE)
mat[4] = matrix(c(4), nrow = 4, ncol = 4, byrow = TRUE)
mat
输出：
> mat = list( matrix (c(1), nrow = 4, ncol = 4, byrow = TRUE),
+ matrix (c(2), nrow = 4, ncol = 4, byrow = TRUE),
+ matrix (c(3), nrow = 4, ncol = 4, byrow = TRUE) )
> mat
[[1]]
[,1] [,2] [,3] [,4]
[1,] 1 1 1 1
[2,] 1 1 1 1
[3,] 1 1 1 1
[4,] 1 1 1 1
[[2]]
[,1] [,2] [,3] [,4]
[1,] 2 2 2 2
[2,] 2 2 2 2
[3,] 2 2 2 2
[4,] 2 2 2 2
[[3]]
[,1] [,2] [,3] [,4]
[1,] 3 3 3 3
[2,] 3 3 3 3
[3,] 3 3 3 3
[4,] 3 3 3 3
> mat[2]
[[1]]
[,1] [,2] [,3] [,4]
[1,] 2 2 2 2
[2,] 2 2 2 2
[3,] 2 2 2 2
[4,] 2 2 2 2
> mat[1] = matrix(c(0), nrow = 4, ncol = 4, byrow = TRUE)
Warning message:
In mat[1] = matrix(c(0), nrow = 4, ncol = 4, byrow = TRUE) :
number of items to replace is not a multiple of replacement length
> mat[4] = matrix(c(4), nrow = 4, ncol = 4, byrow = TRUE)
Warning message:
In mat[4] = matrix(c(4), nrow = 4, ncol = 4, byrow = TRUE) :
number of items to replace is not a multiple of replacement length
> mat
[[1]]
[1] 0
[[2]]
[,1] [,2] [,3] [,4]
[1,] 2 2 2 2
[2,] 2 2 2 2
[3,] 2 2 2 2
[4,] 2 2 2 2
[[3]]
[,1] [,2] [,3] [,4]
[1,] 3 3 3 3
[2,] 3 3 3 3
[3,] 3 3 3 3
[4,] 3 3 3 3
[[4]]
[1] 4