Question

我有一个包含元素的User表单类，并且我正在尝试添加Regex验证器。

这是我尝试过的

$inputFilter->add([
            "name"                   => "password",
            "required"               => true,
            "filters"                => [
            ],
            "validators"             => [
                [
                    "name"           => new Regex(["pattern" => "/^[a-zA-Z0-9_]+$/"]),
                ],
                [
                    "name"           => "NotEmpty",
                ],
                [
                    "name"           => "StringLength",
                    "options"        => [
                        "min"        => 6,
                        "max"        => 64
                    ],
                ],
            ],
        ]);

但是会抛出

Zend \ Validator \ Regex类的对象无法转换为字符串

有人可以帮我吗？

Answer 1

您可以为验证器添加输入过滤器规格，以下应该可以使用

$inputFilter->add([
    "name" => "password",
    "required" => true,
    "filters" => [
    ],
    "validators" => [
        // add validator(s) using input filter specs
        [
            "name" => "Regex",
            "options" => [
                "pattern" => "/^[a-zA-Z0-9_]+$/"
            ],
        ],
        [
            "name" => "NotEmpty",
        ],
        [
            "name" => "StringLength",
            "options" => [
                "min" => 6,
                "max" => 64
            ],
        ],
    ],
]);

如果您确实要实例化对象（如原始代码中那样使用new Regex(...)），则可以使用这种方式代替

$inputFilter->add([
    "name" => "password",
    "required" => true,
    "filters" => [
    ],
    "validators" => [
        // add a regex validator instance 
        new Regex(["pattern" => "/^[a-zA-Z0-9_]+$/"]),
        // add using input filter specs ...
        [
            "name" => "NotEmpty",
        ],
        [
            "name" => "StringLength",
            "options" => [
                "min" => 6,
                "max" => 64
            ],
        ],
    ],
]);

您可能还会发现此zf博客文章Validate data using zend-inputfilter和官方zend-input-filter docs有用

如何在zend的表单类中添加正则表达式验证器

1 个答案: