Question

实时示例this is my sample live website

问题是当我离线使用它时，“ Contact-Us”的代码工作正常（wampserver），但是当我将其上传到cpanel时，它却无法正常工作……我尝试了几乎所有操作，但警报只是向我“连接失败”，Connection.php可以正常工作，我可以连接到数据库，问题似乎出在INSERT语句中。我在代码中看不到任何问题，因为我的其他“注册”表格可以在网上正常运行，请参见示例网站。我的代码没有错误问题，因为我已经检查了错误日志：

    <?php 

include_once 'Connection.php';

if(isset($_POST['btn-index']))
{
 $first_name = $_POST['first_name'];
 $email = $_POST['email'];
 $contact = $_POST['contact'];
 $subject = $_POST['subject'];
 $message = $_POST['workarea'];


$first_name = stripslashes($_REQUEST['first_name']);
$first_name = mysqli_real_escape_string($conn,$first_name);

$email = stripslashes($_REQUEST['email']);
$email = mysqli_real_escape_string($conn,$email);

$contact = stripslashes($_REQUEST['contact']);
$contact = mysqli_real_escape_string($conn,$contact);

$subject = stripslashes($_REQUEST['subject']);
$subject = mysqli_real_escape_string($conn,$subject);

$message = stripslashes($_REQUEST['workarea']);
$message = mysqli_real_escape_string($conn,$message);

$sql = "INSERT INTO `inquiry` (First_Name,Email,Contact,Subj,Message)
VALUES('$first_name','$email','$contact','$subject','$message')";

if($conn->query($sql) === TRUE)
        {
            ?>
            <script>
            alert('Records Submitted!');
            window.location.href='index.php#parent_contacts';
            </script>
            <?php
        }
        else
        {
            ?>
            <script>
            alert('Connection Failed...');
            window.location.href='index.php#parent_contacts';
            </script>
            <?php
        }
$conn->close();
}

//---------FOR ABOUT-US.PHP-------------------------
if(isset($_POST['btn-contact']))
{
 $name = $_POST['name'];
 $email = $_POST['email'];
 $contact = $_POST['contact'];
 $subject = $_POST['subject'];
 $message = $_POST['message'];


$name = stripslashes($_REQUEST['name']);
$name = mysqli_real_escape_string($conn,$name);

$email = stripslashes($_REQUEST['email']);
$email = mysqli_real_escape_string($conn,$email);

$contact = stripslashes($_REQUEST['contact']);
$contact = mysqli_real_escape_string($conn,$contact);

$subject = stripslashes($_REQUEST['subject']);
$subject = mysqli_real_escape_string($conn,$subject);

$message = stripslashes($_REQUEST['message']);
$message = mysqli_real_escape_string($conn,$message);

$sql = "INSERT INTO `inquiry` (First_Name,Email,Contact,Subj,Message)
VALUES('$name','$email','$contact','$subject','$message')";

if($conn->query($sql) === TRUE)
        {
            ?>
            <script>
            alert('Records Submitted!');
            window.location.href='Contact-Us.php';
            </script>
            <?php
        }
        else
        {
            ?>
            <script>
            alert('Connection Failed...');
            window.location.href='Contact-Us.php';
            </script>
            <?php
        }
$conn->close();
}

?>

Answer 1

重新编写代码后，我终于解决了问题。原来问题出在我的SQL表上..行没有排序规则，所有行都变成“ int”，不知道是什么导致了Godaddy myphpAdmin上的触发，但是使用本地时，在我的沼泽上工作得很好

php脚本可以离线运行，但不能在线运行

1 个答案: