Question

我试图通过两种不同的方式从另一个作业中执行作业，但是在第一种情况下，我遇到错误，第二种-不要从包装的作业中检索输出。

这是我的代码：

变种1：

ToAppointments

变种2：

$joba = {
    param(
        $st
    )
    $st | Write-Output
    return $st
}


$jobb = {
    param(
        $strng,
        $ja
    )

    "Trying to execute joba with $strng parameter..." | Write-Output
    Start-Job -Name JA $ja -ArgumentList $strng
    Receive-Job -Name $ja
}

$quack = "woof"
$result = Start-Job -Name JB $jobb -ArgumentList $quack
Receive-Job JB

UPD 1 （情况1的错误消息）：

$jobb = {
    param(
        $strng
    )

    $joba = {
        param(
            $st
        )
        $st | Write-Output
        return $st
    }

    "Trying to execute joba with $strng parameter..." | Write-Output
    $ja = Start-Job -Name JA $joba -ArgumentList $strng
    Receive-Job -Job $ja
}

$quack = "woof"
$result = Start-Job -Name JB $jobb -ArgumentList $quack
Receive-Job JB

Answer 1

嗨，我认为您必须检查此链接，它是关于如何等待工作的说法：

我想这个例子可以帮助您：

   $jobb = {
    param($strng,$ja)

    # $strng |Write-Output
    # $ja | Write-Output
    $joba = {
        param($st)
        Write-Host $st
        return $st
    }


    Write-Host "Trying to execute joba with $strng parameter..." 
    $myRunJobA = Start-Job -Name:"JA"  -ArgumentList:@($strng) -ScriptBlock:$joba
    # $myRunJobA
    $resultJobA = Receive-Job -Job:$myRunJobA -Wait
    # Write-Host $myRunJobA
}

$quack = "woof"
$myRunJobB = Start-Job -Name:"JB" -ArgumentList:@($quack) -ScriptBlock:$jobb
$resultJobB = Receive-Job -Job:$myRunJobB -Wait

是否可以从其他工作开始工作？

1 个答案: