文件中有两个矩阵,格式如下:
17.053 24 1 8 15
23 5 7 14 16
4 6 13 20 22
10 12 19 21 3
11 18 25 2 9
1 3 1 4
0 5 0 4
2 1 2 4
这些只是两个矩阵,它们始终以空行分隔。它们可以是任何大小和形状。我有以下代码读取两个矩阵,并找出每个矩阵的行数和列数。如何将它们输入定义为mat_A
和mat_B
的两个矩阵中?
我尝试了fscanf,但只打印了0。如何读取应该保存两个二维数组的值?
int main(void)
{
int space_count = 0;
int i = 0;
int j = 0;;
FILE *fp;
fp = fopen("inputformat", "r");
if(fp == NULL)
printf("File not read!");
int NumCols_first, NumCols_second, NumRows_first, NumRows_second;
int issecondmatrix = 0;
char *line = NULL;
size_t len = 0;
ssize_t read;
double **mat_A = (double **) malloc(NumRows_first * sizeof(double*));
for(i=0; i<NumRows_first; i++)
mat_A[i] = (double *) malloc(NumCols_first * sizeof(double));
double **mat_B = (double **) malloc(NumRows_second * sizeof(double*));
for(i=0; i<NumRows_second; i++)
mat_B[i] = (double *) malloc(NumCols_second * sizeof(double));
while((read = getline(&line, &len, fp)) != -1){
printf("Line is of length : %u \n", read);
printf("Line is:%s\n", line);
for(i=0; i<read; i++){
printf("%c\n", line[i]);
if(line[i] == ' ')
space_count++;
if(read == 1){
printf("Next matrix gonna start after this\n");
NumRows_first = j;
issecondmatrix = 1;
j = 0;
}
}
if(j==1 & issecondmatrix == 0)
NumCols_first = space_count + 1;
if(j==1 & issecondmatrix == 1)
NumCols_second = space_count + 1;
space_count = 0;
j++;
}
NumRows_second = j - 1;
printf("num of columns in first matrix is %d\n", NumCols_first);
printf("number of rows in first matrix is %d\n", NumRows_first);
printf("num of columns in second matrix is %d\n", NumCols_second);
printf("num of rows in second matrix is %d\n", NumRows_second);
for(i=0; i<NumRows_first)
{
for(j=0; j<NumCols_first; j++)
{
if(!(fscanf(fp, "%lf", &mat_A[i][j]))
break;
printf("%lf", mat_A[i][j]);
}
}
enter code here
free(line);
fclose(fp);
}
答案 0 :(得分:0)
示例代码中有几个错误,显而易见的一个错误是在分配内存之前未启动矩阵大小。您可以先扫描文件以找到矩阵的大小并分配内存,然后第二遍扫描以填充矩阵;或者您可以先分配足够大的内存,然后在扫描文件时将其填满。这是一个工作示例,其中忽略了许多错误检查(对于较短的代码)。
#include <stdio.h>
#include <ctype.h>
#include <stdlib.h>
#include <assert.h>
#include <string.h>
int parse_empty(char *word)
{
for(; *word!='\0'; word++)
if(!isspace(*word))
break;
return (*word=='\0');
}
int parse_line(char *line, float *data, int max)
{
int n=0; char *p=line, *left=line;
while((p=strchr(left, ' '))!=NULL) {
*p='\0';
if((n<max) && (!parse_empty(left))) {
data[n] = atof(left);
n++;
}
left = p+1;
}
if(!parse_empty(left)) {
data[n] = atof(left);
n++;
}
return n;
}
#define MAX_LINESZ 128
void parse_matrix(FILE *fp, float *data, int max, int *mm, int *nn)
{
int m=0, n=0; char *line; size_t len=MAX_LINESZ;
line = malloc(len*sizeof(char));
while(getline(&line, &len, fp)!=-1) {
if(parse_empty(line))
break;
n = parse_line(line, data, max);
data = data+n;
max = max-n;
m++;
}
free(line);
*mm=m; *nn=n;
}
//data must be malloc/calloc memory!
float **matrix_realloc(float *data, int max, int m, int n)
{
assert(max>=m*n);
float **mat;
mat = malloc(m*sizeof(float*));
mat[0] = realloc(data, m*n*sizeof(float));
for(int i=1; i<m; i++)
mat[i] = mat[i-1]+n;
return mat;
}
void matrix_free(float **matrix)
{
free(matrix[0]);
free(matrix);
}
#define MAX_MATRIX (8*8)
int main()
{
float *data1, *data2;
int m1, m2, n1, n2;
FILE *fp = fopen("t.dat", "r");
data1 = malloc(MAX_MATRIX*sizeof(float));
data2 = malloc(MAX_MATRIX*sizeof(float));
parse_matrix(fp, data1, MAX_MATRIX, &m1, &n1);
parse_matrix(fp, data2, MAX_MATRIX, &m2, &n2);
float **mat1 = matrix_realloc(data1, MAX_MATRIX, m1, n1);
float **mat2 = matrix_realloc(data2, MAX_MATRIX, m2, n2);
for(int i=0; i<m1; i++) {
printf("1>");
for(int j=0; j<n1; j++)
printf(" %8.2f", mat1[i][j]);
printf("\n");
}
for(int i=0; i<m2; i++) {
printf("2>");
for(int j=0; j<n2; j++)
printf(" %8.2f", mat2[i][j]);
printf("\n");
}
matrix_free(mat1);
matrix_free(mat2);
fclose(fp);
return 0;
}