symfony嵌套查询

Question

如何使用symfony和doctrine queryBuilder执行嵌套查询？ 例如：

select data.name from
(
  select case when name = 'Alfred' then 'Thomas' else name end as name
  from employee
) as data;

谢谢

Answer 1

我使用本地sql解析：

    $stmt = $this->doctrine->getConnection()->prepare('your_query');
    $stmt->execute();
    $res = $stmt->fetchAll();