我有MySQL MyISAM表:
表朋友(id,friend_id):
1,5
5,1
2,6
6,2
3,7
如何删除反向记录?如果记录值“1,5”存在值为“5,1”的记录,我需要删除“5,1”。
Thanx寻求帮助!
答案 0 :(得分:7)
DELETE F1
FROM friends F1, friends F2
WHERE F1.friend_id = F2.id
AND F2.friend_id = F1.id
AND F1.id > F1.friend_id
修改强>
更好的语法是:
DELETE F1
FROM friends F1
JOIN friends F2 ON F1.friend_id = F2.id AND F2.friend_id = F1.id
WHERE F1.id > F1.friend_id
但执行时间是一样的。
同样,我已经快速创建了this small script&肮脏的基准。
<强>结果:强>
没有索引:
Dalen: 600 => 400 rows. Time: 0.0274 Mark: 600 => 400 rows. Time: 0.4323 Frosty: 600 => 400 rows. Time: 0.4081 Nick: 600 => 400 rows. Time: 0.3201
列id
和friend_id
上的单独索引:
Dalen: 600 => 400 rows. Time: 0.0201 Mark: 600 => 400 rows. Time: 0.0095 Frosty: 600 => 400 rows. Time: 0.0059 Nick: 600 => 400 rows. Time: 0.3257
(id, friend_id)
上的唯一索引:
Dalen: 600 => 400 rows. Time: 0.0168 Mark: 600 => 400 rows. Time: 0.0057 Frosty: 600 => 400 rows. Time: 0.0041 Nick: 600 => 400 rows. Time: 0.3209
结论:
答案 1 :(得分:3)
试试这个:
create temporary table tmp
select a.* from friends as a,friends as b
where a.id = b.friend_id
and a.friend_id = b.id /* left out of original post */
and a.id < b.id;
delete from friends using friends inner join tmp
on friends.id = tmp.id
and friends.friend_id=tmp.friend_id;
如果朋友表非常大,则联接比其他方法更有效。
编辑:我修复了上面的“创建...选择”语句。测试它,工作正常。对不起!
答案 2 :(得分:2)
DELETE FROM friends
WHERE (id,friend_id) IN
(
SELECT * FROM
(
SELECT t1.id,t1.friend_id
FROM friends t1 JOIN friends t2
ON t1.id=t2.friend_id AND t1.friend_id = t2.id
WHERE t1.id > t1.friend_id
) t3
)
答案 3 :(得分:1)
create table friends (
id int,
friend_id int ) engine = myisam;
insert into friends values (1,5),(5,1),(2,6),(6,2),(3,7);
delete from friends where (id,friend_id) in
(select * from (
select id,friend_id from friends
union all
select friend_id,id from friends ) as t
where id > friend_id
group by id,friend_id
having count(*) > 1)