Question

我具有以下HTML结构。想要选择标签

的值为3.x

我尝试了以下xpath表达式

$resId = 11;


$counter = 0;
$ids=array(17,34,51,68,85,102,119,136,153,170,187,204,221,238,255,272,289,306,323);

$stmt = $pdo->prepare( 'select * from `lappu` where `resturantid` = :id' );
$stmt->bindParam( ':id', $resId );
$stmt->execute();

$codes=array();

while( $row = $stmt->fetch( PDO::FETCH_ASSOC ) ) {
    $codes[ $row['resturantid'] ] = $row['code'];
    $counter++;
}








for( $x = 1; $x <= $counter; $x++ ) {
    if ( in_array( $x, $ids ) ) {

        $code=$codes[ $x ];

        for ( $b = 1; $b <= 16; $b++ ) {
            echo 'pictures'.'<br>';
        }

        for ( $b = 1; $b <= 16; $b++ ) {
            echo $code.'<br>';
        } 
    }
}

但是没有用。收到异常"//label[contains(@class='options')]/div/p[contains(text(),'3.x')]" "//div[@class='answerOpts']/label[contains(@class='options')]/div/p[contains(text(),'3.x')]"。您能告诉我解决方法吗？

HTML结构

org.openqa.selenium.NoSuchElementException: Unable to locate element:

Answer 1

尝试在xpath以下

.// div / p [text（）='3.x'] / parent :: div / parent :: label / preceding-sibling :: input [1]

Answer 2

下面是一些xpath示例，您如何获取label元素：

//label[normalize-space(.)='3.x']
//label[contains(@class,'options') and .//p[.='3.x']]
//label[contains(@class,'options') and @for and .//p[.='3.x']]
//p[.='3.x']/ancestor::label[1]
//p[.='3.x']/ancestor::label[contains(@class,'searchable')][1]

Selenium Java选择基于嵌套元素文本的div

2 个答案: